*Originally posted by talzamir*

**Is it possible to divide any triangle ABC into three parts by choosing points D and E on the side BC so that the angles CAD, DAE and EAB are all equal, and that the lengths BD = DE = EC = BC / 3 ?**

No (if I understand the question correctly), the positions D and E can be found by trisecting D&E, which can be done with compass and straight-edge:

http://www41.homepage.villanova.edu/robert.styer/trisecting%20segment/

If the angles were also equal then BAC would have been trisected with compass and straight edge, which is impossible.

http://en.wikipedia.org/wiki/Angle_trisection