A lot of 9.

Originally posted by kbaumen
I'll post some others I found:

sin9sin9 + cos9cos9 + 9 = 10
(99 - 9)/9 + derivative(9) = 10 (I suppose if you derive a constant function, hence a constant number, the derivative is 0)
(tg9ctg9 + 9) * 9 / 9 = 10

Eh, yeah, there really are tons of possibilities.

Ok, let's make 1 to 100 with five 9. (with only + - * /, hence no trigonometry, logarith ...[text shortened]... sions, calculus, combinatorics and other creepy stuff)

I'll start:

1 = (99 - 9) / 9 - 9

there goes the ``about creepy stuf ``!


anyway...........WOW!

Originally posted by alexdino
there goes the ``about creepy stuf ``!


anyway...........WOW!

yeah.. didn't read from beginning...
but sqrt x = x^(1/2), it doesn't make a lot of sense to use it too....
I guess 43 is impossible with only those combinations...

43= sqrt(9)*9 + sqrt(9)*9 -9/9 ->another with six "9" .

44 = ( 9^sqrt(9) ) /9 - 9*Sqrt(9)
45 = 9 + 9 + 9 + 9 + 9 (hard one)

Originally posted by serigado
yeah.. didn't read from beginning...
but sqrt x = x^(1/2), it doesn't make a lot of sense to use it too....
I guess 43 is impossible with only those combinations...

43= sqrt(9)*9 + sqrt(9)*9 -9/9 ->another with six "9" .

are you sure? (53)

Originally posted by alexdino
are you sure? (53)

well... guess 53 is done .. ehhe

i cant figure this out without !.

46= [((sqrt9)!)*((sqrt9)!)]+9+(9/9)

47 seems even more impossible without the use of log base 9...can we adjust the rules?

47 = 9 * (sqrt 9)! - (sqrt 9) ! - 9/9

48 = (9 + (sqrt 9)! + 9/9) + sqrt 9
49 = 9 * (sqrt 9)! -((sqrt 9)! - 9/9)
50 = 9 * (sqrt 9)! - ((Sqrt 9 ) + 9/9)

51 = 9 * (sqrt 9)! -(9-9+sqrt 9)
52 = 9 * (sqrt 9)! - (sqrt 9 - 9/9)
53 is hard

Originally posted by afx
53 is hard

It's not that bad

53 = 9 x (sqrt(9) + sqrt(9)) - 9/9
54 = 9 x (sqrt(9) + sqrt(9)) - 9 + 9
55 = 9 x (sqrt(9) + sqrt(9)) + 9/9

56 = 9 * (sqrt 9)! + (9+9)/9
57 = 9 * (sqrt 9)! + 9-9+sqrt 9
58 = 9 * (sqrt 9)! + (Sqrt 9 ) + 9/9
59 = 9 * (sqrt 9)! + (sqrt 9)! - 9/9
60 = 9 * (sqrt 9)! + (sqrt 9) ! +9-9

61= ((sqrt9)!)*9+((sqrt9)!)+(9/9)
62= ((sqrt9)!)*9+((sqrt9)!)+(((sqrt9)!)/(sqrt9))
63= ((sqrt9)!)*9+((sqrt9)!)+(((sqrt9)!)-(sqrt9))
64= (((sqrt9)!)*9)+9+(9/9)
65= (((sqrt9)!)*9)+9+(((sqrt9)!)/(sqrt9))
66= (((sqrt9)!)*9)+9+(((sqrt9)!)-(sqrt9))

p.s. please excuse all my parentheses, its just how my trig class has influenced me =P

I think, 66 is a good number to stop the project now.
With the sqrt9-trick for 3, the (sqrt9)!-trick for 6 and
the the (sqrt9)!/sqrt9 for 2 and the ^9 trick
( (9/9)^9=1, (9-9)^9=0)
the rest is just easy going

i agree, the rest would just be all a matter of time. i think it is safe to say we have succeeded 😀