1. Joined
    12 Jul '08
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    13814
    09 Jun '19 13:52
    @iamatiger said
    @Eladar

    No probs eladar, I like these puzzles venda!
    Yeah, you have good number sense and reasoning. Way better than most.

    Any particular reason you chose 13?

    People generally enjoy what they are good at.
  2. Subscribervenda
    Dave
    S.Yorks.England
    Joined
    18 Apr '10
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    83688
    09 Jun '19 14:52
    @iamatiger said
    @Eladar

    No probs eladar, I like these puzzles venda!
    Thanks for that tiger.
    As I thought there is a trial and error element but the clues are there to lead you in the right direction.
    As you like this sort of thing, here's another:-
    2 cars set off from the same point to travel the same journey
    The first car has a 9 minute start.
    The first car travels at 80km/h
    The second car travels at 95km/h
    How many km from the start will the cars draw level?
  3. Joined
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    13814
    09 Jun '19 15:061 edit
    @venda said
    Thanks for that tiger.
    As I thought there is a trial and error element but the clues are there to lead you in the right direction.
    As you like this sort of thing, here's another:-
    2 cars set off from the same point to travel the same journey
    The first car has a 9 minute start.
    The first car travels at 80km/h
    The second car travels at 95km/h
    How many km from the start will the cars draw level?
    That one is a much easier question.

    9 min is .15 hours

    80×.15 is 12, so the first car has a 12 km lead.

    The second car is traveling 15 km per hour faster than the first. Using d= rt...
    12=15t and solving for t you get .8 hours.

    .8 hours is 40 minutes.
  4. Subscribervenda
    Dave
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    09 Jun '19 15:13
    @eladar said
    That one is a much easier question.

    9 min is .15 hours

    80×.15 is 12, so the first car has a 12 km lead.

    The second car is traveling 15 km per hour faster than the first. Using d= rt...
    12=15t and solving for t you get .8 hours.

    .8 hours is 40 minutes.
    Maybe so.
    But that is not the question.
    The answer is the distance travelled when the cars are level
  5. Joined
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    09 Jun '19 15:142 edits
    @venda

    Well if it takes 40 min to be even then multiply .8 by the speed of the second car.

    95 x.8 =76 km.

    So yeah always make sure you are answering the question.
  6. Subscribervenda
    Dave
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    09 Jun '19 15:17
    @eladar said
    @venda

    Well if it takes 40 min to be even then multiply .8 by the speed of the second car.

    95 x.8 =76 km.

    So yeah always make sure you are answering the question.
    Yes.
    Well done
  7. Joined
    26 Apr '03
    Moves
    26771
    09 Jun '19 22:13
    @venda
    D= S1 * S2 * t / (S1 - S2)
    D= 90 * 80 * 9/60 /15
    D= 90*80*9/(60*15)
    D= 90*8*9/(6*15)
    D= 90*8*9/90
    D=8*9
    D=72
  8. Joined
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    09 Jun '19 23:263 edits
    @iamatiger

    Cool formula. What is it based on?

    t is obviously the difference in starting times not the time one of the cars is traveling.

    It gave us different answers.

    The slower car doing 80 would be traveling .95 hours also resulting in 76.

    Ok found your error. You used 90 km per hour instead of 95.
  9. Joined
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    13814
    10 Jun '19 00:27
    9.5×8 results in 76
  10. Joined
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    26771
    10 Jun '19 08:292 edits
    @Eladar

    Thanks Eladar, car-less of me!
    Formula is that is car at S1 has a head start of t, it goes a distance ofS1*t
    The delta speed of the two cars is (S2-S1)
    So the time for the second car to catch up is
    (S1 * t)/(S2 -S1)
    The final distance is S2 * time so we have:
    Final distance = D = S1*S2*t/(S2 - S1)

    Interestingly this rearranges to
    t/D = 1/S1 - 1/S2
  11. Standard memberwolfgang59
    Quiz Master
    RHP Arms
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    10 Jun '19 08:56
    @eladar said

    .8 hours is 40 minutes.
    0.8 hours is 48 minutes.
  12. Joined
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    13814
    10 Jun '19 12:27
    @wolfgang59 said
    0.8 hours is 48 minutes.
    Good thing I calculated with hours.
  13. Joined
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    Moves
    13814
    10 Jun '19 12:291 edit
    @iamatiger said
    @Eladar

    Thanks Eladar, car-less of me!
    Formula is that is car at S1 has a head start of t, it goes a distance ofS1*t
    The delta speed of the two cars is (S2-S1)
    So the time for the second car to catch up is
    (S1 * t)/(S2 -S1)
    The final distance is S2 * time so we have:
    Final distance = D = S1*S2*t/(S2 - S1)

    Interestingly this rearranges to
    t/D = 1/S1 - 1/S2
    Yeah thought about it. You just made a formula of the steps I went through. In the US we like to use basic formulas then build answers instead of simplified formulas for specific cases.

    Nice pun, just got it lol.
  14. Subscribervenda
    Dave
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    10 Jun '19 12:56
    @iamatiger
    You're obviously a very qualified mathematician.
    What level have you achieved academically?
    I detested mathematics at school but later in life my interest was sparked when I saw a problem in a newspaper about someone trying to fill up a bath with the plug out!!(why would yo do that?)
    I couldn't work it out and it annoyed me so I got a book out of the library and it all started from there.
    People then started buying me mathematical puzzle books for birthdays and xmas which is where most of the ones I put on here come from
  15. Standard memberAThousandYoung
    or different places
    tinyurl.com/2tp8tyx8
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    10 Jun '19 16:25
    @eladar said
    Good thing I calculated with hours.
    Math teacher lol
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