Originally posted by wolfgang59 Correct - rather nice I think.
I don't think it's as nice as the other result. After all, with i^i you have an answer that isn't complex so, in that sense, I find it an elegant result.
Of course, "nice" is not a mathematical term. 🙂
Originally posted by Palynka I don't think it's as nice as the other result. After all, with i^i you have an answer that isn't complex so, in that sense, I find it an elegant result.
Of course, "nice" is not a mathematical term. 🙂
What is nicer, n!=1x2x...xn or sqrt(2*Pi*n)*((n^n)/(e^n))?
Originally posted by genius What is nicer, n!=1x2x...xn or sqrt(2*Pi*n)*((n^n)/(e^n))?
What does that have to do with anything?
The answer to this second problem requires an expression that depends on i, while the first one has an answer defined in Real numbers. That's the difference.
+-(1 + i)/sqrt(2) doesn't seem much different than leaving it as sqrt(i).
Originally posted by Palynka What does that have to do with anything?
The answer to this second problem requires an expression that depends on i, while the first one has an answer defined in Real numbers. That's the difference.
+-(1 + i)/sqrt(2) doesn't seem much different than leaving it as sqrt(i).
the first looks nice, visually, while the second is much easier to see the value churned out, and easier to work with. They are approximatly equal, for large n.
Originally posted by genius the first looks nice, visually, while the second is much easier to see the value churned out, and easier to work with. They are approximatly equal, for large n.
I'm sorry, but I still don't understand what your point is...
Square root of minus one
05 Nov '07 12:45
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