22 Sep '17 22:48>1 edit
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Originally posted by @humyHe was making reference to my comment about the cot term in the link's formula.
how does that make the formula wrong?
Why is the formula wrong if it is based on the radius and not the side?
The formula is correct; just not the one you asked for.
This is just semantics but you should say that as "correct but not the one I ask for" (or alternative words of that effect) and not just "wrong". I apologize for being annoyingly pedantic; 🙂 I do that a lot.
Originally posted by @sonhouseI developed a method of finding the equation for a polynomial based sequence a few years ago. It uses subtraction of terms, the rebuild using integration. It required one more term than the degree of the polynomial.
Still, you have to hand it to him for coming up with a way different from the approved method.
I did a similar thing with gravitational lensing, I came up with a formula for calculating focal length based on radius and mass, introducing a new constant in it only to be told here it was not original, but at least it was my own work independent of the pape ...[text shortened]... He is no doubt very busy right now with a dozen students and his own ongoing research projects.
Originally posted by @eladarIsn't that easy? Perimeter P of a regular n-gon with sides of length s is simply P=n*s, so replace s with P/n in the formula.
The purpose was to find the area using perimeter and specifically perimeter.
Radius and apothem based formulas are common enough.
Originally posted by @soothfastYep, that was the idea. Then after squaring one set of n's cancel, leaving p squared over 4n. Taking the limit as n approaches infinity would result in the area of a circle. Have no clue how that would work out.
Isn't that easy? Perimeter P of a regular n-gon with sides of length s is simply P=n*s, so replace s with P/n in the formula.
Originally posted by @eladarEven the old Greeks knew that...
Yep, that was the idea. Then after squaring one set of n's cancel, leaving p squared over 4n. Taking the limit as n approaches infinity would result in the area of a circle. Have no clue how that would work out.
Originally posted by @fabianfnasYes, but they did not know how to take linits and were limited to measurements to calculate circumference.
Even the old Greeks knew that...
Originally posted by @eladarJust tested it in my ti84 and it works.
Just did a quick set of calculations and if they are right, using the link's nicer trig component....
The limit as n approaches infinity of n*tan (180/n) equals pi.
Fixed, forgot to square my 2.
Originally posted by @eladarDoes your formula work in non-Euclidean spaces, too?
The purpose was to find the area using perimeter and specifically perimeter.
Radius and apothem based formulas are common enough.
Originally posted by @moonbusI've never studied them so I don't know. Based on what little I just read about them I doubt it. Distances are not consistent so no distances formulas should work.
Does your formula work in non-Euclidean spaces, too?
Originally posted by @eladarStill old news...
Yes, but they did not know how to take linits and were limited to measurements to calculate circumference.