11 Feb 12
I think the answer you seek is 0 K.
Outside my window the ratio has been uncomfortably close to one a few times this winter.. the downside of living next door to Santa.
Who doesn't live on the North Pole, it's just disinformation given by the elves so that the big man can work in peace.
11 Feb 12
Originally posted by talzamirYour box has nothing in it, nothing comes up.
[hidden]I think the answer you seek is 0 K.[/hidden]
Outside my window the ratio has been uncomfortably close to one a few times this winter.. the downside of living next door to Santa. [hidden]Who doesn't live on the North Pole, it's just disinformation given by the elves so that the big man can work in peace.[/hidden]
11 Feb 12
Originally posted by joe shmoPretty close, 1.728. I saw there was a range where only one temperature would have a particular ratio, on the positive C side, the numbers asymptote towards 1.8 but on the negative side, since -273.15 is absolute zero, the ratio can't get to 1.8. It can if you allow say -300,000 C, which of course is a nonsense number.
I'm going to say no such ratio can exist, but close enough happens @ -26.2 C
I was just playing with my casio calculator which has the C-F and F-C conversions and saw you could specify a ratio that would only work on the negative C side.
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11 Feb 12
Originally posted by sonhouseWhen I said
Pretty close, 1.728. I saw there was a range where only one temperature would have a particular ratio, on the positive C side, the numbers asymptote towards 1.8 but on the negative side, since -273.15 is absolute zero, the ratio can't get to 1.8. It can if you allow say -300,000 C, which of course is a nonsense number.
I was just playing with my casio ca ...[text shortened]... F-C conversions and saw you could specify a ratio that would only work on the negative C side.
(C/F) =/= Sqrt(3)
Is because the irrational sqrt(3) cannot be expressed as the ratio of two integers
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14 Feb 12
2 edits
9C/5+32=F
C=160/(5F/C-9)
F=160/(5-9C/F)
I think temperature is a measure of the square of the average speed of a group of particles. As long as the particle speed can be irrational temperature can therefore be irrational, so this depends on whether speed is quantised or not.
Since there is no consensus on whether time and distance are quantised, nobody knows for sure whether speed is quantised, and so nobody knows whether an irrational temperature is possible.
14 Feb 12
1 edit
Originally posted by joe shmoInteresting point with regard to temperature. You can measuire irrational lengths though for instance by using diagonals of rectangles with rational dimensions. Maybe I will have a word with the physics department see if they can come up with a plan (problem is they always want to round to a reasonable degree of accuracy).
But can you measure irrational values?
14 Feb 12
Originally posted by deriver69There is no mening to measure irrational values of temperatures. But this doesn't mean that irrational values of temperatures doesn't exist.
Interesting point with regard to temperature. You can measuire irrational lengths though for instance by using diagonals of rectangles with rational dimensions. Maybe I will have a word with the physics department see if they can come up with a plan (problem is they always want to round to a reasonable degree of accuracy).
When a temp of 3 degree rises to 4 degrees, then every real value in between has been passed during the process. Even exactly pi degrees. Not for long though.
14 Feb 12
Originally posted by FabianFnasCan you imagine the circuitry needed to make a temperature exactly PI C?
There is no mening to measure irrational values of temperatures. But this doesn't mean that irrational values of temperatures doesn't exist.
When a temp of 3 degree rises to 4 degrees, then every real value in between has been passed during the process. Even exactly pi degrees. Not for long though.