This weeks puzzle

@bigdoggproblem said

A 24 hour digital clock shows each digit using a 7 segment display.The digits 0-9 use 6,2,5,5,4,5,6,3,7,6 segments respectively.Starting from 00:00, how many times a day does the display change but still have the same total number of segments in use?
Good luck.
I don't even understand the question!!
There are no typo's -I've checked it 3 times

...[text shortened]... d my answer using Python. For those interested in coding: https://repl.it/repls/FloweryChiefResource

@venda said
Congratulations again.
As with a lot of these things, it's quite straight forward when you see the answer.
The Boa constrictor snake you used for verification must be a very clever one!!

This weeks puzzle is mildly entertaining.Sounds a bit like social distancing to me!! :-
As I was going to St Ives I met a man with seven wives,each wife had seven cats , each cat had seven kits.Kit's Cats,wives , man and I stood in a straight line , each keeping precisely two metres apart(as measured from the centre of one body to the next).
how long was the line

@venda said
This weeks puzzle is mildly entertaining.Sounds a bit like social distancing to me!! :-
As I was going to St Ives I met a man with seven wives,each wife had seven cats , each cat had seven kits.Kit's Cats,wives , man and I stood in a straight line , each keeping precisely two metres apart(as measured from the centre of one body to the next).
how long was the line

@joe-shmo said
n = 1+1+7+7^2 + 7^3 = 401 Things in a line

Distance = 2* ( n-1) = 2*( 401 - 1 ) = 800 m

The puzzle in last weeks Saturday paper was quite interesting although I didn't know how to do it.(Sorry, I've been busy!!)
It was an ice cream parlour that offered any combination of 5 flavours of Ice cream on the menu.
Because of restrictions they then were now only offering any combination of 4 flavours on the menu.
How many combinations were there on offer now?
The only other fact you were given was that there were now exactly half of the options available than there was before.
I've seen the(frankly ridiculous ) answer and I know the combinations formula but I can't work out how to set about it when the N! is an unknown

@venda said
The puzzle in last weeks Saturday paper was quite interesting although I didn't know how to do it.(Sorry, I've been busy!!)
It was an ice cream parlour that offered any combination of 5 flavours of Ice cream on the menu.
Because of restrictions they then were now only offering any combination of 4 flavours on the menu.
How many combinations were there on offer now?
T ...[text shortened]... d I know the combinations formula but I can't work out how to set about it when the N! is an unknown

@bigdoggproblem said
Are there any restrictions on the number of scoops per combination?

@venda said
Sorry, I think I missed a bit.
The combination of flavours offered was a combination of any 5 and 4 from "x" number of flavours.
The problem therefore is finding when any 5 out of x is double any 4 out of x where x is the number of flavours on the menu.

@wolfgang59
Incorrect

@venda

Hi Venda

I think N=14, which would give 2002 ways of choosing 5 flavours and 1001 of choosing 4?

@blood-on-the-tracks said
@venda

Hi Venda

I think N=14, which would give 2002 ways of choosing 5 flavours and 1001 of choosing 4?

@venda

Well, the ways of picking r things from N is given by N!/(N-r)!r!

So I had N!/(N-5)!5! for the 5 scoops and N!/(N-4)!4! for 4

So N!/(N-5)!5! = 2 x N!/(N-4)!4!

Your N! cancels out, turn 'both sides' upside down and you get

(N-5)! x 5! = (N-4)! x 4! all over 2

5!/4! =5 and (N-4)!/(N-5)! = (N-4), so applying that to cancelling we get

5 = (N-4)/2

10 = N-4, N=14, then apply the combinations rule from earlier to get 1001 and 2002

Phew!

@blood-on-the-tracks said
@venda

Well, the ways of picking r things from N is given by N!/(N-r)!r!

So I had N!/(N-5)!5! for the 5 scoops and N!/(N-4)!4! for 4

So N!/(N-5)!5! = 2 x N!/(N-4)!4!

Your N! cancels out, turn 'both sides' upside down and you get

(N-5)! x 5! = (N-4)! x 4! all over 2

5!/4! =5 and (N-4)!/(N-5)! = (N-4), so applying that to cancelling we get

5 = ...[text shortened]... -4)/2

10 = N-4, N=14, then apply the combinations rule from earlier to get 1001 and 2002

Phew!

@venda
No problem. Have missed your weekly 'puzzle', though you did say the quality dwindled!