Go back
Mate in one

Mate in one

Only Chess

Vote Up
Vote Down

Originally posted by SwissGambit
Look at the White King and Queen. They're on the wrong color, and there is no way they could have switched places if White is playing up the board. Therefore, White is playing down the board.
That is exactly the point that proves the solution.

Well detected!

Vote Up
Vote Down

Originally posted by JonathanB of London
That is exactly the point that proves the solution.

Well detected!
white queen? cant see that piece

Vote Up
Vote Down

Originally posted by peterh
white queen? cant see that piece
You are looking at a different solution. This is for:

http://streathambrixtonchess.blogspot.com/2008/03/white-to-play.html

Vote Up
Vote Down

Originally posted by lausey
You are looking at a different solution. This is for:

http://streathambrixtonchess.blogspot.com/2008/03/white-to-play.html
yeah that's right ... this thread has got confusing because we've started discussing two different problems - one of which you have to click on a link to get to see.

1 edit
Vote Up
Vote Down

Originally posted by JonathanB of London
That is exactly the point that proves the solution.

Well detected!
Well remembered, rather. The proof is that your diagram is wrong - wPg2 is needed to keep Bf1 shut in [to prove that those squares aren't really g2 and f1!]

Edit: And for some reason, the Smullyan diagram has bNf6 [c3, once proof is applied].

Vote Up
Vote Down

Originally posted by lausey
Ahhh, sussed it out. Square a1 is at the top right, so white is playing down the board. Nf6# 🙂

Thought it was impossible at first as I went through every combination which does a check (with the board the usual way round, there aren't that many, just Nh6+, Nf6+ and Rh8+).
Ha, wrong! Knight can't get to f6. However, Nc3# works.

Vote Up
Vote Down

Originally posted by SwissGambit
Well remembered, rather. The proof is that your diagram is wrong - wPg2 is needed to keep Bf1 shut in [to prove that those squares aren't really g2 and f1!]

Edit: And for some reason, the Smullyan diagram has bNf6 [c3, once proof is applied].
Here's the correct diagram:


Mate in 1

Vote Up
Vote Down

Originally posted by kbaumen
Ha, wrong! Knight can't get to f6. However, Nc3# works.
Oops. 😕

Vote Up
Vote Down

Originally posted by SwissGambit
Well remembered, rather. The proof is that your diagram is wrong - wPg2 is needed to keep Bf1 shut in [to prove that those squares aren't really g2 and f1!]

Edit: And for some reason, the Smullyan diagram has bNf6 [c3, once proof is applied].
Oh you're right.

I had to change the diagram from when I first published it because I'd made a minor mistake elsewhere and obviously these errors crept into the corrected version - thanks for pointing this out.

I'll correct the blog now.


J

Vote Up
Vote Down

But back to the original problem, I see mate in 5 using contemporary rules ...

1.bxa8=Q+ Kxa8 2.Kc6 Kb8 3.Rh7 Ka8 4.Kb6 Kb8 5.Rh8#

Is there a quicker method?

Vote Up
Vote Down

Originally posted by dinosaurus
But back to the original problem, I see mate in 5 using contemporary rules ...

1.bxa8=Q+ Kxa8 2.Kc6 Kb8 3.Rh7 Ka8 4.Kb6 Kb8 5.Rh8#

Is there a quicker method?
1. bxa8=Q+ Kxa8 2. Kb6! Kb8 3. Rc? anything but c8 Ka8 4. Rc8#