Originally posted by greenpawn34Yep - an explanation's needed.Rookbycrook seems to have it right.
[fen]8/p1Pp1ppN/R1p4p/Pp4P1/K6p/2PP2P1/kqQrP3/rNbB4 w - - 0 1[/fen]
That is White in checkmate.
[fen]8/p1Pp1ppN/R1p4p/Pp4P1/2K4p/2PP2P1/kqQrP3/rNbB4 w - - 0 1[/fen]
White checkmates with 1. axb6 ep.
Of course S.G. maye be wanting an explanation as to why it can be proved
that en passant can be played in the 2nd diagram and not the first.
Originally posted by greenpawn34The white pawn could have taken (b6xc7), and then the black b-pawn could have stepped forward twice (...b6 and ...b5).
[fen]8/p1Pp1ppN/R1p4p/Pp4P1/7p/2PP2P1/kqQrP3/rNbB4 w - - 0 1[/fen]
The Black pawn on h4 has come from e7 so it cannot have taken from g5.
The White pawn on c7 is the White b-pawn it has taken something from
b6 so no Black pawn on b6. So the b-pawn is on b7.