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In attack
Joined 02 Mar '06 Moves 30138 Rh4, Qxc8, Nd5#
Rh4, Qc7, Nd5#
Rh4, Qc6, Nd5#
Rh4, Qc5, Nd5#
Rh4, Nc4, Bd2#
it was more complicated
Rh4, Nb3, Rxb3#
and again
Rh4, Nd2, Bg7#
...
Rh4, d6, Qh8#
Rh4, d5, Qh3#
I sincerely hope I have covered my bases this time...
2014.05.01
Joined 11 Apr '07 Moves 92274 Originally posted by morgski
[hidden]...[/hidden]
1.Rh4 Nc4 2.Bd2+ Kxd4
In attack
Joined 02 Mar '06 Moves 30138 Did you mean Nxd2? There is nothing on d4 for K to x
Revised again:
Q
Rh4, Qxc8, Nd5#
Rh4, Qc7, Nd5#
Rh4, Qc6, Nd5#
Rh4, Qc5, Nd5#
N1
Rh4, Nc4, Rxb3#
Rh4, Nb3, Rxb3#
Rh4, Nxb7, Rxb3#
N2
Rh4, Nd2, Bg7#
P
Rh4, d6, Qh8#
Rh4, d5, Qh3#
In attack
Joined 02 Mar '06 Moves 30138 Re4, Rf4 and Rg4 don't work because then he's in the way of B1, B2 or Q for one of the above examples
2014.05.01
Joined 11 Apr '07 Moves 92274 Originally posted by morgski
Did you mean Nxd2? There is nothing on d4 for K to x
Yeah, of course I meant 2.Nxd2! 😛
SOLV'D
Fort Gordon
Joined 24 Jan '11 Moves 13644 Originally posted by Fat Lady
I thought there were two solutions to this, but I've just worked out why one of them fails. My incorrect solution didn't have a mate after 1. (move) d7-d5, although it did after 1. (move) d7-d6. 1.Qxa5 Qc4 2.Nd5 checkmate
Fort Gordon
Joined 24 Jan '11 Moves 13644 Originally posted by Fat Lady
That last one isn't mate, Black can recapture with his b-pawn. 1.Qxa5 Qc4 2.Nd5 checkmate
Fort Gordon
Joined 24 Jan '11 Moves 13644 Originally posted by Fat Lady
The rook on d4 is hanging!
Okay, I see.
Fort Gordon
Joined 24 Jan '11 Moves 13644 Originally posted by morgski
Did you mean Nxd2? There is nothing on d4 for K to x
He must have put a lot of time in to come up with that mate in 2 puzzle.
P.S.
Rh4, Nc4, Rb3#
Rh4, Nxb7, Rb3#
2014.05.01
Joined 11 Apr '07 Moves 92274 Originally posted by RJHinds
1.Qxa5 Qc4 2.Nd5 checkmate Kxd4
This time I really mean it.
Joined 12 Aug '09 Moves 8489 A pleasant problem. The bPa3 drew my attention. It isn't needed in the initial position, as either 1 ... Na3 or 1 ... Nd2 would be met with 2 B(x)d2. Why, then, did the composer wish to prevent 1 ... Na3? The answer is that 2 Bd2 does not occur post-key. 1 Rh4 Nd2 2 Bg7 is a self-block, but 1 ... Na3 wouldn't be, and 2 Bg7 would leave d2 unguarded.
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05 Oct '12 16:05
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Problem 4
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