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Posers and Puzzles
Joined 31 May '07 Moves 696 wait wait wait, if 44 isn't allowed, then my entry for 10 needs to be changed.
Joined 09 Jun '07 Moves 1416 R
Removed
Joined 10 Dec '06 Moves 8528
Joined 31 May '06 Moves 34901 44 is OK. 4 squared is not (there is a 2 in squared) SQRT (4) is OK but not cube root (4) (as there is a 3). All 4's must be used, so 4+4+4=12 is no good.
Going well, but get back on track guys.
Joined 31 May '06 Moves 34901 R
Removed
Joined 10 Dec '06 Moves 8528 but sqrt(4) = 4^1/2 there is a 2 (index)
Joined 31 May '06 Moves 34901 Originally posted by joe shmo
but sqrt(4) = 4^1/2 there is a 2 (index) There is a common symbol for sqrt(x), and it doesn't use the 2. I know that the 2 is implied, but it's not actually there - so it is allowed.
Joined 31 May '06 Moves 34901 Up to 10 was OK.
44/(sqrt(4)*sqrt(4))=11
Joined 25 Mar '07 Moves 8974 (4*4)-sqrt(4)-sqrt(4) = 12
Joined 25 Mar '07 Moves 8974
Joined 25 Mar '07 Moves 8974
Joined 25 Mar '07 Moves 8974 4*4-(4/4) = 15
4+4+4+4 = 16
Joined 31 May '07 Moves 696
Sigulda, Latvia
Joined 30 Aug '06 Moves 4048 Originally posted by Gastel
4^(4-4)*4 = 4[/b]Wrong. 4^0=1; (4-4)*4=0
Correct. 4^1=4; 4^(4/4)=4^1=4
converging to it
Joined 21 Aug '06 Moves 11463 4+(4*4)-sqrt(4) = 18
4!-4-(4/4) = 19
(44-4)/sqrt(4) = 20
4!-4+(4/4) = 21
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