08 Apr '05 07:10

Suppose two co-workers each take one lunch break per day. They arrive at the cafeteria independently at random times between 12 PM and 1 PM, and each stays for exactly x minutes. The probability that either co-worker arrives while the other is in the cafeteria is 40%.

If x = a - b*(c)^0.5, then find (a + b + c).

You also are given: a, b, and c are positive integers. And c is not divisible by the square of any prime number.

I found this problem on a standardized mathematics exam, and I have worked it out several times, always getting the same answer. But my answer differs slightly from their answer sheet (I think they have a misprint). I am hoping that one of you can solve it to either confirm my answer or show me why my answer is wrong.

cheers,

If x = a - b*(c)^0.5, then find (a + b + c).

You also are given: a, b, and c are positive integers. And c is not divisible by the square of any prime number.

I found this problem on a standardized mathematics exam, and I have worked it out several times, always getting the same answer. But my answer differs slightly from their answer sheet (I think they have a misprint). I am hoping that one of you can solve it to either confirm my answer or show me why my answer is wrong.

cheers,