#### Posers and Puzzles

Norway

- Joined
- 19 Dec '02
- Moves
- 483

Given:

a = b

Multiply with a on both sides:

a^2 = ab

a^2 + (a^2 - 2ab) = ab + (a^2 - 2ab)

2a^2 - 2ab = a^2 - ab

2(a^2 - ab) = 1(a^2 - ab)

2 = 1

How is this possible? Anything wrong somewhere?

Elsewhere

- Joined
- 29 Nov '02
- Moves
- 17317

Since a=b, a^2=ab, so a^2-ab=0. Thus in the final step you divided by 0.

Norway

- Joined
- 19 Dec '02
- Moves
- 483

I'm impressed of your quick problem-solving. ðŸ™‚

I really like that problem. Still, I was hoping that at least _one_ person would answer wrong... *sob*

ðŸ˜›

Elsewhere

- Joined
- 29 Nov '02
- Moves
- 17317

Thanks. No problem then. WHen you post a problem, I'll give it at least half an hour before I post ðŸ˜›.

Norway

- Joined
- 19 Dec '02
- Moves
- 483

Hehehe. Don't worry about it. From now on, I'm only posting new problems when you are asleep. ðŸ™‚

However, if you've got a problem, please feel free to make a new thread ... ðŸ˜›

*sits down, waiting for a new problem to pop up*