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Posers and Puzzles

Posers and Puzzles

  1. 17 Jun '03 00:33
    Given:
    a = b

    Multiply with a on both sides:
    a^2 = ab
    a^2 + (a^2 - 2ab) = ab + (a^2 - 2ab)
    2a^2 - 2ab = a^2 - ab
    2(a^2 - ab) = 1(a^2 - ab)
    2 = 1

    How is this possible? Anything wrong somewhere?
  2. Standard member royalchicken
    CHAOS GHOST!!!
    17 Jun '03 00:38
    Since a=b, a^2=ab, so a^2-ab=0. Thus in the final step you divided by 0.
  3. 17 Jun '03 00:42
    I'm impressed of your quick problem-solving.

    I really like that problem. Still, I was hoping that at least _one_ person would answer wrong... *sob*

  4. Standard member royalchicken
    CHAOS GHOST!!!
    17 Jun '03 00:44 / 1 edit
    Thanks. No problem then. WHen you post a problem, I'll give it at least half an hour before I post .
  5. 17 Jun '03 00:54
    Hehehe. Don't worry about it. From now on, I'm only posting new problems when you are asleep.

    However, if you've got a problem, please feel free to make a new thread ...

    *sits down, waiting for a new problem to pop up*