Originally posted by heinzkat Yes, I noticed how stupid the question is after posting. 🙂
i'm still trying to learn how these puzzles work... kinda like a retro problem (i'm also new to those)? i.e. since there are 5 minimum pawn captures made by white, and 5 missing pieces for black, there are no missing black pieces? is that why the question was no good?
Yes. Black has no last move again - it cannot have been b7-b6 or e7-e6 because Black's Bishops are already missing, and they have been captured by the white pawns to double them.
I think Black's last move was -1...c2-c1=R which makes the bRc1 the bPh7, capturing five units on its way on the white squares, RBNNQ. The DSB can't have been captured on this road. White is allowed to add one piece, the DSB.
Originally posted by Aetherael i'm still trying to learn how these puzzles work... kinda like a retro problem (i'm also new to those)? i.e. since there are 5 minimum pawn captures made by white, and 5 missing pieces for black, there are no missing black pieces? is that why the question was no good?
Yes, this is indeed a retro problem, and you are on the right track: All of black's missing pieces were captured by white pawns, so none can be legally placed on the board.
Originally posted by heinzkat Yes. Black has no last move again - it cannot have been b7-b6 or e7-e6 because Black's Bishops are already missing, and they have been captured by the white pawns to double them.
I think Black's last move was -1...c2-c1=R which makes the bRc1 the bPh7, capturing five units on its way on the white squares, RBNNQ. The DSB can't have been captured on this ...[text shortened]...
[fen]8/p1pp1pp1/1p2p3/2P5/PB2P3/P1P3P1/1K1kPP2/r1rqR3 w - -[/fen]
Add pieces and mate in 2
28 Jan '09 23:52
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