- 09 May '07 13:13 / 1 editIs the differential of z = xe^(y^2)

e^(y^2)dx + 2yxe^(y^2)dy ?

EDIT:

If homogeneous, find the degree of homogeinity of the function:

f(x,y) = xg(y/x), where g is an arbitrary function of one variable.

>no idea how to solve this< all I end up with is txg(ty/tx)...g(ty)?

Don't go studying economics :'( - 09 May '07 18:16 / 1 edit

First part looks right. Here's a link that might help with your second question:*Originally posted by emanon***Is the differential of z = xe^(y^2)**

e^(y^2)dx + 2yxe^(y^2)dy ?

EDIT:

If homogeneous, find the degree of homogeinity of the function:

f(x,y) = xg(y/x), where g is an arbitrary function of one variable.

>no idea how to solve this< all I end up with is txg(ty/tx)...g(ty)?

Don't go studying economics :'(

http://en.wikipedia.org/wiki/Homogeneous_differential_equation

Looks like the equation you've described is a first-degree homogeneous equation.