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Posers and Puzzles

Posers and Puzzles

  1. 28 Jun '06 18:36
    I am the boss. and I have employee 1, employee 2, employee 3.

    I give them 90 apples distributed in the following order:

    Employee 1: 50 apples
    Employee 2: 30 apples
    Employee 3: 10 apples

    My order is that they have to sell all apples at the same prize employee 1 sells them, if he sells them two for a dollar, then the others must do so, and they must sell all apples, an by doing this they must obtain the same amount of money, if employee one obtains 5 dollars for the 50 apples, then employee two must have obtained 5 dollars for his 30 apples, and employee one as well.

    At what prize do they have to sell the apples?
  2. Standard member XanthosNZ
    Cancerous Bus Crash
    28 Jun '06 18:40
    1 for $0
  3. 28 Jun '06 18:42
    Originally posted by XanthosNZ
    1 for $0
    The answer is not $0,
  4. Standard member PBE6
    Bananarama
    28 Jun '06 18:43 / 1 edit
    "Sell" them for free.

    EDIT: Too late.
  5. 28 Jun '06 19:23
    of course they are free they are prizes.

    (50 apples)*price = 30 apples* price

    50-30=20 apples* price = 0 => price = 0

    perhaps you meant something else?
  6. Standard member uzless
    The So Fist
    28 Jun '06 19:32
    Originally posted by Superman
    I am the boss. and I have employee 1, employee 2, employee 3.

    I give them 90 apples distributed in the following order:

    Employee 1: 50 apples
    Employee 2: 30 apples
    Employee 3: 10 apples

    My order is that they have to sell all apples at the same prize employee 1 sells them, if he sells them two for a dollar, then the others must do so, and they mus ...[text shortened]... s for his 30 apples, and employee one as well.

    At what prize do they have to sell the apples?
    Buy 1 apple for $5 and get all the rest of the employee's apples for free
  7. 28 Jun '06 19:54
    Originally posted by aginis
    of course they are free they are prizes.

    (50 apples)*price = 30 apples* price

    50-30=20 apples* price = 0 => price = 0

    perhaps you meant something else?
    My english is not very good, I meant "price". but the problen has a logical solution and it is not a word game, there is a way to sell all apples an obtain the same amount of money for each employee following the rules.

    Hint: you can sell them in diferent packs.
  8. 28 Jun '06 20:01
    Originally posted by Superman
    My english is not very good, I meant "price". but the problen has a logical solution and it is not a word game, there is a way to sell all apples an obtain the same amount of money for each employee following the rules.

    Hint: you can sell them in diferent packs.
    then any price will do
    1 sells 50 apples for $x
    2 sells 30 apples for $x
    3 sells 10 apples for $x

    or

    1 sells 25,10,5 for $x each = 2x,5x,10x respectively
    2 sells 15,6,3 for $x = 2x, 5x,10x respectively
    3 sells 5,2,1 for $x each = 2x,5x,10x respectively

    and the price x is irrelevent
  9. 28 Jun '06 20:07
    Originally posted by aginis
    then any price will do
    1 sells 50 apples for $x
    2 sells 30 apples for $x
    3 sells 10 apples for $x

    or

    1 sells 25,10,5 for $x each = 2x,5x,10x respectively
    2 sells 15,6,3 for $x = 2x, 5x,10x respectively
    3 sells 5,2,1 for $x each = 2x,5x,10x respectively

    and the price x is irrelevent
    sell them in packs so that the prize is the same, imagine that they went out two times to sell them, and by imposible reasons the price had, they could not sell them all the first time, so they regrouped, rearanged the price for the last ones and finished.

    this hint is too much i think, I am going out now be back in a few hours
  10. 28 Jun '06 20:42
    Originally posted by Superman
    sell them in packs so that the prize is the same, imagine that they went out two times to sell them, and by imposible reasons the price had, they could not sell them all the first time, so they regrouped, rearanged the price for the last ones and finished.

    this hint is too much i think, I am going out now be back in a few hours
    ok, its not a hint if the question doesn't make sense. you have to set some sort of rules.

    once again the price could be anything
    day1 employee 1 sells 49 apples for 261 dollars a piece netting $12,789
    employee's 2 and 3 have a slow day and sell no apples

    day2 employee 1 is trying to sell his last apple for 441 dollars but fails
    employee 2 sells 29 apples at 441 each netting 12,789
    employee 3 has a slow day no sales

    day 3 employee 1 is selling his last apple at 1421
    he and employee 2 fail
    but employee sells 9 apples and the brooklyn bridge for $12,789

    day 4 blow out sale all three employees sell their last remaining apple for $1 each nets $12790

    do me a favor don't become a math teacher (i hear McDonalds is hiring.)
  11. 29 Jun '06 03:45
    Originally posted by aginis
    ok, its not a hint if the question doesn't make sense. you have to set some sort of rules.

    once again the price could be anything
    day1 employee 1 sells 49 apples for 261 dollars a piece netting $12,789
    employee's 2 and 3 have a slow day and sell no apples

    day2 employee 1 is trying to sell his last apple for 441 dollars but fails
    employee 2 sells 29 a ...[text shortened]... 1 each nets $12790

    do me a favor don't become a math teacher (i hear McDonalds is hiring.)
    Yes, I guess you are right, you reached the solution, only in a different way than the one I have, but it is like you said, it doesn’t mater the amount, so this problem has as much solutions as numbers, unless you make a rule for that.

    Here is the solution I have.

    Employee 1 started selling seven apples per dollar, so she sold 49 apples obtaining 7 dollars, and 1 apple left.

    Employee 2 was obliged to sell the same so he sold 28 apples obtaining 4 dollars, and 2 apples left.

    Employee 3 did the same and sold 7 apples obtaining 1 dollar and 3 apples left.

    Because it was impossible to sell 7 apples for them, they regrouped and employee 1 set a new price:

    Employee 1 sold his remaining apple for 3 dollars
    Employee 2 did the same with his apples and obtained 6 dollars
    Employee 3 did the same with his 3 apples and obtained 9 dollars

    So employee 1 has 7 dollars the first sale and 3 the second equals 10
    And employee 2 has 4 dollars the first sale and 6 the second equals 10
    Employee 3 had 1 dollar from the first sale and 9 the second it equals 10

    I guess the rule would be to sell the apples at a reasonable price, because who would buy an apple for 441 dollars?

    I will take your advice, wont be a teacher.