Originally posted by petrovitch
When asked about the results of their blitz games, Bobby Fischer said, "We played the same number of games. Larry won two-thirds of his games and I lost only one of mine."
Larry Evans added, 'We didn't draw any games and between us the two of us won three-quarters of our games."
How many games did Larry Evans and Bobby Fischer play?
If we let Lw and Lp be the number of games Larry won and played, respectively; and let Bw and Bp be the number of games Bobby won and played respectively; then we have the following equations.
1. Lw = (2/3)Lp
2. Lp = Bp
3. Bw = Bp-1
4. Lw + Bw = (3/4)(Lp + Bp)
Together, these entail that Lp = Bp = 6.
So each played in 6 games with Bobby going 5-1 and Larry going 4-2.
However, if your question is how many distinct games this comprises, then I think there is not enough information. For instance, there could have been as many as 12 distinct games or as few as 9 (since, given the information, Larry and Bobby could have played against each other in as many as 3 of the games).