Originally posted by uzlessAnalyze what happens with 14 players:
Again, mulitiples of 1-6.
If total number of players end back to 1 (1,7,13,19 etc), pick table 1
If total number ends at 2 pick table 2
If total number ends at 3 pick table 1
If total number ends at 4, makes no difference
If total numbers end at 5, it makes no difference.
If total number ends at 6, it makes no difference.
The first 12 are logically placed 2 on 1, 4 on 2, 6 on 3.
Player 7's best choice is 3.
Player 8's best choice is 2.
What are the payouts?
Table 1 players get 1,000/2 = 500
table 2 players get 2,000/5 = 400
table 3 players get 3,000/7 = 428
So your strategy of choosing table 2 in that case is faulty.
The solution for players > 6 is ALWAYS choose table 1.