There are three glasses of water with capacity of 3oz, 5oz and 8oz each. The last glass(8oz) is full, the others are empty. Transfer the water in such a way that one glass contains 4oz.
Only one condition: you cannot pour or fill half/quarter glass etc.for eg you cannot pour half of the water in the 8oz glass to the 5oz glass to get 4oz. Understand what i mean?
Enjoy😏
Originally posted by arterioes5 oz from 8 to 5.
There are three glasses of water with capacity of 3oz, 5oz and 8oz each. The last glass(8oz) is full, the others are empty. Transfer the water in such a way that one glass contains 4oz.
Only one condition: you cannot pour or fill half/quarter glass etc.for eg you cannot pour half of the water in the 8oz glass to the 5oz glass to get 4oz. Understand what i mean?
Enjoy😏
3 oz from 5 to 3.
Now we have 3 in 8, 2 in 5, 3 in 3.
3 oz from 3 to 8. 2 oz from 5 to 3. 5 oz from 8 to 5.
Now we have 1 in 8, 5 in 5, 2 in 3.
1 oz from 5 to 3 leaves 4 oz in 5.
1 edit
Originally posted by arterioesDon't know if it's the least moves....
Good. Now can you get 4oz in the 8oz glass.🙂
3 from 8 to 3, and then 3 from 3 to 5 - leaves 5,3,0 (in 8,5,3, respectively)
3 from 8 to 3, and then 2 from 3 to 5 - leaves 2,5,1
5 from 5 to 8, and then 1 from 3 to 5 - leaves 7,1,0
finally, 3 from 8 to 3 - leaves 4,1,3