1. Standard memberEnglish Tal
    Phoneless
    Account suspended
    Joined
    01 Jun '06
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    25553
    22 May '07 22:06
    .. and missed the answer.

    It sounds easy at first, I guess, but I must've missed something. One of you out there will probably send the answer whilst I'm still typing this!
    Ok... how far does one have to go, counting up from one, using the spelling of each number, until a letter 'a' is reached?
  2. Joined
    25 Mar '07
    Moves
    8974
    22 May '07 22:19
    I would say "one thousand"
  3. Joined
    25 Mar '07
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    8974
    22 May '07 22:20
    That is wierd... i never thought of it before.
  4. Joined
    21 Feb '06
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    6830
    22 May '07 22:28
    One hundred and one.
  5. Joined
    17 Mar '07
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    207
    22 May '07 23:28
    Traditionally, the "and" doesn't count. Martin Gardner presents the problem this way:

    10^3, 10^9, 10^100, 10^2, ?

    The idea is that 10^3 is the first number containing A, 10^9 is the first containing B, etc. After the fifth term it gets less pretty, since the first one containing F is "four," i.e. 10^(log 4).
  6. Standard memberirontigran
    Rob Scheider is..
    A Stapler!
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    26 Jun '06
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    59283
    22 May '07 23:31
    a one and a two and a three...
  7. Joined
    17 Dec '06
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    8208
    23 May '07 05:49
    Originally posted by jvanhine
    a one and a two and a three...
    lol
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