This may be kinda easy for some of you geniuses in here, but I thought it introduced a kinda neat idea for the solution. I was doing this problem for my P121 class, so it's pretty elementary.
A car traveling at constant speed reaches the crest of a huge frost heave(cylindrical cross section with radius of 70m). What is the max spped the car can travel without becoming airborne at the crest? The great thing is that the solution is pretty concise, and the lack of information in this problem also makes it pretty cool!
Nice work! Here is the work, although I am sure noone really cares....
Fnet = ma --> Obviously start with this
N - W = m(v^2/r) --> Ac = v^2/r in Uniform Circular Motion
N + mg = m(v^2/r) --> W = mg
g = (v^2/r) --> When N = 0, the force of ground on car = 0
v = (rg) ^ (1/2)
Nice job, although pretty easy...I should post some of the crap my professor puts on the exam!