1. Standard memberAlex011893
    The High Rate Clan
    USA
    Joined
    30 Jun '05
    Moves
    28666
    05 Aug '05 04:04
    Here is a challenge.On a board,place 12 knights so all the squares on the board are occupied or threatened.Good Luck.

    🙂🙂😉😀
  2. Standard memberskeeter
    515 + 30 days
    Account suspended
    Joined
    08 Mar '03
    Moves
    38202
    05 Aug '05 05:311 edit
    Originally posted by Alex011893
    Here is a challenge.On a board,place 12 knights so all the squares on the board are occupied or threatened.Good Luck.

    🙂🙂😉😀
    This should do it.



    skeeter
  3. Standard memberskeeter
    515 + 30 days
    Account suspended
    Joined
    08 Mar '03
    Moves
    38202
    05 Aug '05 05:35
    Originally posted by skeeter
    This should do it.

    [fen]8/5n2/1nn1nn2/2n5/5n2/2nn1nn1/2n5/8[/fen]

    skeeter
    What I've just noticed is that the board is also perfectly asymetrical.

    skeeter
  4. Joined
    29 Apr '05
    Moves
    827
    05 Aug '05 09:16
    Since it's solved, here's something amazing that i found recently about the so called knight tour. If you scroll down a bit (to the colored section) you will find the "SUPER magic square"....awesome, how the numbers in all columns, rows and quadrants add up in perfection.

    http://www.edcollins.com/chess/knights-tour.htm
  5. Standard memberPalynka
    Upward Spiral
    Halfway
    Joined
    02 Aug '04
    Moves
    8702
    05 Aug '05 13:191 edit
    Originally posted by crazyblue
    Since it's solved, here's something amazing that i found recently about the so called knight tour. If you scroll down a bit (to the colored section) you will find the "SUPER magic square"....awesome, how the numbers in all columns, ro ...[text shortened]... in perfection.

    http://www.edcollins.com/chess/knights-tour.htm
    That's quite amazing. Anyone has a maths explanation for this? It can't be a coincidence...can it?
  6. Standard memberAlex011893
    The High Rate Clan
    USA
    Joined
    30 Jun '05
    Moves
    28666
    05 Aug '05 16:45
    thanks to all.🙂
  7. Joined
    05 Dec '04
    Moves
    9647
    12 Aug '05 12:49
    Originally posted by skeeter
    This should do it.

    [fen]8/5n2/1nn1nn2/2n5/5n2/2nn1nn1/2n5/8[/fen]

    skeeter
    how did you insert the chess board graphic?
  8. Standard memberAlex011893
    The High Rate Clan
    USA
    Joined
    30 Jun '05
    Moves
    28666
    12 Aug '05 17:59
    that is easy..
  9. Joined
    21 May '05
    Moves
    4255
    25 Aug '05 23:38
    place all 8 queens on the board that each other wont treaten or pass each other.
  10. Joined
    30 Oct '04
    Moves
    7797
    26 Aug '05 16:39
    Originally posted by inipsianini
    place all 8 queens on the board that each other wont treaten or pass each other.
    While this has already been done I did notice the word "all" that you placed before the 8 queens. Now the number of all possible queens would be 18 (2 from the beginning and 16 promoted). However I am uncertain if there is a legal sequence of moves leading to such position, and if there is, what is the shortest game that produces 18 queens?
  11. Joined
    12 Mar '03
    Moves
    37189
    26 Aug '05 17:05
    Originally posted by ilywrin
    While this has already been done I did notice the word "all" that you placed before the 8 queens. Now the number of all possible queens would be 18 (2 from the beginning and 16 promoted). However I am uncertain if there is a legal sequence of moves leading to such position, and if there is, what is the shortest game that produces 18 queens?
    16 promoted queens is not possible. There are only 7 non-pawn pieces reach side to capture. A pawn has to capture something to get behind the opposing pawn.
  12. Joined
    30 Oct '04
    Moves
    7797
    26 Aug '05 20:42
    Originally posted by Mephisto2
    16 promoted queens is not possible. There are only 7 non-pawn pieces reach side to capture. A pawn has to capture something to get behind the opposing pawn.
    I may be counting wrong but here's my idea: both sides have 6 spare pieces to be captured (excluding the queens and kings).
    White gets 3 pawns at the g file with two captures (f and h pawn), 3 pawns at the d file with two more captures (c and e pawn) and lastly one more capture to get two pawns at b file (a-pawn); Black in similar manner get 3 on c and f files and h and a file pawns remain on their files. That's 5 captures from White and 4 on Black's part, accounting for 9 of the twelve spare pieces. Then the queens are promoted on the respective files.
  13. Earth Prime
    Joined
    16 Mar '05
    Moves
    21936
    26 Aug '05 21:28
    Originally posted by ilywrin
    I may be counting wrong but here's my idea: both sides have 6 spare pieces to be captured (excluding the queens and kings).
    White gets 3 pawns at the g file with two captures (f and h pawn), 3 pawns at the d file with two more captures (c and e pawn) and lastly one more capture to get two pawns at b file (a-pawn); Black in similar manner get 3 on c and f f ...[text shortened]... counting for 9 of the twelve spare pieces. Then the queens are promoted on the respective files.
    It's possible. Just did it. No PGN sorry. It was utterly long, but not hard. Just a matter of moving stuff around.
Back to Top