Posers and Puzzles
28 Mar 06
Originally posted by Balla88Yes, I think youre right.
[b]I think he meant that 0 is not part of the set of natural numbers. b]
Sometimes "!=" is pronounced "not equal to" (used by programmers), and in this case "r != 0" mening "r not equal to zero" says that r can be any natural number except zero. For example 42.
Originally posted by XanthosNZIf you have n distinct chocolates, there are n! possible arrangements in total. To find out how many have a distinct wrapped chocolate at the end, we designate one to be put at the end and arrange the rest, so the number of possible arrangements here is (r choose 1)*(n-1)!. The probability that the chocolates will be selected in an order represented by the second group is then:
Postulate:
Given a mixed box of chocolates containing n distinct chocolates, r of which are wrapped, there is a greater than r/n chance that the last remaining chocolate will be wrapped.
Assumptions:
n > r
r != 0
n,r are natural numbers.
P = (r choose 1)*(n-1)! / n!
= r*(n-1)! / n!
= r / n
There must be some trick I'm missing.
Aren't the wrapped chocolates usually the ones with alcohol inside? Maybe the majority of chocolate eaters doesnt like alcohol in chocolates. Especially during daytime when they have to work etc and shouldnt get drunk yet. 😀
But I also think it's the fact that its wrapped. People are just too lazy.
Originally posted by crazyblueWrapped chocolates look like they'll last longer so ppl will eat the others first.
Aren't the wrapped chocolates usually the ones with alcohol inside? Maybe the majority of chocolate eaters doesnt like alcohol in chocolates. Especially during daytime when they have to work etc and shouldnt get drunk yet. 😀
But I also think it's the fact that its wrapped. People are just too lazy.