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Posers and Puzzles

Posers and Puzzles

  1. 03 Nov '11 23:26
    Using only 3,3,8 and 8

    You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle
  2. 04 Nov '11 02:14
    3 factorial / (3rd root of 8) * 8
  3. Subscriber joe shmo
    Strange Egg
    04 Nov '11 02:45
    Originally posted by Nybes
    [hidden]3 factorial / (3rd root of 8) * 8 [/hidden]
    clever, but the number 1 is used in that expression.
  4. Standard member talzamir
    Art, not a Toil
    04 Nov '11 06:47 / 1 edit
    3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

    method 2:
    square root of (3 x 3 x 8 x 8) and other variants on the theme


    method 3;
    8 + 8 + (square root of (3 x 3)) !


    method 4;
    8 + 8 + 3 + 3


    method 5;
    LCM(LCM(3, 3) , LCM(8,8)); least common multiple
  5. 04 Nov '11 10:06
    Originally posted by talzamir
    3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

    method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

    method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

    method 4; [hidden]8 + 8 + 3 + 3[/hidden]

    method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]
    method 3 is wrong it adds to make 22
  6. Subscriber joe shmo
    Strange Egg
    04 Nov '11 12:38
    Originally posted by talzamir
    3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

    method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

    method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

    method 4; [hidden]8 + 8 + 3 + 3[/hidden]

    method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]
    cube root, sure its own mathematical operator, but it represents x^(1/3)?
  7. Subscriber joe shmo
    Strange Egg
    04 Nov '11 12:40 / 1 edit
    Originally posted by talzamir
    3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

    method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

    method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

    method 4; [hidden]8 + 8 + 3 + 3[/hidden]

    method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]
  8. 04 Nov '11 18:58
    Joe, the notation for x'th root of n is fairly well accepted as the following.

    x ____
    \/ n

    While the above could also be expressed as "n^(1/x)" it need not be. The simpler expression above is both easier on the eye and more economical.
  9. Standard member talzamir
    Art, not a Toil
    04 Nov '11 19:16
    Well, it the cubic root is out, square root = the 1/2 th power, is also out.

    Fortunately, (3 + 8/8) x 3! = 4 x 6 = 24

    should be okay, so there is still a solution.
  10. 04 Nov '11 22:48 / 2 edits
    Originally posted by Silverstriker
    Using only 3,3,8 and 8

    You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle
    Using Excel, it's simply ROUND(8*3,(3/8))

    3/8 can be 8/3, 3+8, 83, etc. Same result.

  11. 04 Nov '11 23:03 / 1 edit
    I like

    3!/3*8+8
    3!*(3+8/8)
    sqrt((3*3)!/8!)*8
    sqrt(3/3+8)*8
  12. 05 Nov '11 11:17
    This is one of my favorite games as you can changed the numbers and result to achieve.

    The rules can be a bit tougher though. Use only + - * / and brackets to get 24 with
    a) 3 3 8 8
    b) 3 3 7 7

    I think the answer for a) hasn't been posted above yet.
  13. 05 Nov '11 15:57
    Originally posted by Silverstriker
    Using only 3,3,8 and 8

    You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle
    Use base 9 and add them up?

    If that uses "9" then using base 10 uses "10".
  14. Standard member talzamir
    Art, not a Toil
    05 Nov '11 16:15
    only brackets and +-x/ .. hmm..

    38 - 8 - 3! = 30 - 6 = 24; this is not acceptable, then as factorial is out?
    3 / .3 + 7 + 7 = 10 + 7 + 7 = 24; is this okay, (ab)using a decimal point?
  15. 06 Nov '11 08:15
    Originally posted by talzamir
    only brackets and +-x/ .. hmm..

    38 - 8 - 3! = 30 - 6 = 24; this is not acceptable, then as factorial is out?
    3 / .3 + 7 + 7 = 10 + 7 + 7 = 24; is this okay, (ab)using a decimal point?
    you are right, in 1st one factorial is not alright and using 38 as number isn't either. you can use only 3 and 8 separated.

    in 2nd you are right about not using decimals.