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Make 24

Posers and Puzzles

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Using only 3,3,8 and 8

You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle

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3 factorial / (3rd root of 8) * 8

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Originally posted by Nybes
[hidden]3 factorial / (3rd root of 8) * 8 [/hidden]
clever, but the number 1 is used in that expression.

1 edit
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3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

method 2:

square root of (3 x 3 x 8 x 8) and other variants on the theme


method 3;
8 + 8 + (square root of (3 x 3)) !


method 4;
8 + 8 + 3 + 3


method 5;
LCM(LCM(3, 3) , LCM(8,8)); least common multiple

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Originally posted by talzamir
3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

method 4; [hidden]8 + 8 + 3 + 3[/hidden]

method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]
method 3 is wrong it adds to make 22

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Originally posted by talzamir
3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

method 4; [hidden]8 + 8 + 3 + 3[/hidden]

method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]
cube root, sure its own mathematical operator, but it represents x^(1/3)?

1 edit
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Originally posted by talzamir
3! / cubic root of 8 x 8 = 6 / 2 x 8 = 3 x 8 = 24 seems perfectly valid to me? Where's the one?

method 2: [hidden] square root of (3 x 3 x 8 x 8) and other variants on the theme[/hidden]

method 3; [hidden]8 + 8 + (square root of (3 x 3)) ! [/hidden]

method 4; [hidden]8 + 8 + 3 + 3[/hidden]

method 5; [hidden]LCM(LCM(3, 3) , LCM(8,8)); least common multiple[/hidden]

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Joe, the notation for x'th root of n is fairly well accepted as the following.

x ____
\/ n

While the above could also be expressed as "n^(1/x)" it need not be. The simpler expression above is both easier on the eye and more economical.

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Well, it the cubic root is out, square root = the 1/2 th power, is also out.

Fortunately, (3 + 8/8) x 3! = 4 x 6 = 24

should be okay, so there is still a solution. 🙂

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Originally posted by Silverstriker
Using only 3,3,8 and 8

You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle
Using Excel, it's simply ROUND(8*3,(3/8))

3/8 can be 8/3, 3+8, 83, etc. Same result.

😀

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I like

3!/3*8+8
3!*(3+8/8)
sqrt((3*3)!/8!)*8
sqrt(3/3+8)*8

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This is one of my favorite games as you can changed the numbers and result to achieve.

The rules can be a bit tougher though. Use only + - * / and brackets to get 24 with
a) 3 3 8 8
b) 3 3 7 7

I think the answer for a) hasn't been posted above yet.

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Originally posted by Silverstriker
Using only 3,3,8 and 8

You have to use all four numbers - you can use any mathematical symbol that you wish. There are at least four ways of solving the puzzle
Use base 9 and add them up?

If that uses "9" then using base 10 uses "10".

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only brackets and +-x/ .. hmm..

38 - 8 - 3! = 30 - 6 = 24; this is not acceptable, then as factorial is out?
3 / .3 + 7 + 7 = 10 + 7 + 7 = 24; is this okay, (ab)using a decimal point?

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Originally posted by talzamir
only brackets and +-x/ .. hmm..

38 - 8 - 3! = 30 - 6 = 24; this is not acceptable, then as factorial is out?
3 / .3 + 7 + 7 = 10 + 7 + 7 = 24; is this okay, (ab)using a decimal point?
you are right, in 1st one factorial is not alright and using 38 as number isn't either. you can use only 3 and 8 separated.

in 2nd you are right about not using decimals.