- 15 Aug '07 00:10So, Im taking caculus this year and its day two and I already can't remember formulas of the past.

Write a general linear equation for the line through the two points. [In this book a general linear equation is ax + by = c rather than ax + by + c = 0]

points : (-2, 1), (2, -2)

therefore : m = -3/4 so y = -3/4x but how to find c? [y intercept]

Thanks for the help! - 15 Aug '07 00:37

Use the equation y = -3/4x + c Plug in one of the two coordinate pairs for x and y. If you use (-2, 1) then 1 = (-3/4)*-2 + c Then solve for c.*Originally posted by Drew L***So, Im taking caculus this year and its day two and I already can't remember formulas of the past.**

Write a general linear equation for the line through the two points. [In this book a general linear equation is ax + by = c rather than ax + by + c = 0]

points : (-2, 1), (2, -2)

therefore : m = -3/4 so y = -3/4x but how to find c? [y intercept]

Thanks for the help! - 15 Aug '07 15:51

I don't think that's a bad idea. I need help occasionally and I love helping others when I can. However, I don't really think that there would be enough posts in it to warrant reading.*Originally posted by Gastel***We get enough of these that we should start an "I need help with my homework" forum group.**