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Posers and Puzzles

Joined 08 Sep '06 Moves 785 how do u integrate square root of sinx.

Isle of Misfit Toys

Joined 08 Aug '03 Moves 35961 Originally posted by The Avenger
how do u integrate square root of sinx. so where are all the "smart" guys now, huh?

too busy in other threads telling people what they can and can't post, I imagine.

ðŸ˜ž

tinyurl.com/y2c6j2t3

Joined 23 Aug '04 Moves 24791 Originally posted by The Avenger
how do u integrate square root of sinx. "These integrals do not have closed forms in terms of elementary

functions, but they are reducible to elliptic integrals of the

first and second kinds.

You can find the definition of elliptic integrals in most books."

http://groups.google.co.uk/group/sci.math/msg/3087fcde6ade8786?dmode=source&hl=en

I don't know what that means unfortunately.

False berry

Joined 14 Feb '04 Moves 28719 Originally posted by The Avenger
how do u integrate square root of sinx. Handy website:

http://integrals.wolfram.com/index.jsp

Joined 20 Feb '06 Moves 8407 Originally posted by Suzianne
so where are all the "smart" guys now, huh?
too busy in other threads telling people what they can and can't post, I imagine.
ðŸ˜ž Erm...well you've not exactly given much time for the "smart guys" to answer before writing this.

As already mentioned, that integral won't have a nice answer in terms of elementary functions.

A numerical approximation, on the other hand, is straightforward.

Joined 21 Jul '04 Moves 13381 Originally posted by The Avenger
how do u integrate square root of sinx. The answer is you can't

slatington, pa, usa

Joined 28 Dec '04 Moves 52874 Originally posted by The Avenger
how do u integrate square root of sinx. I input (sin x)^.5 and got an answer, its pretty long. At Intregals.wolfram.com

Joined 21 Jul '04 Moves 13381 Originally posted by sonhouse
I input (sin x)^.5 and got an answer, its pretty long. At Intregals.wolfram.com You'd have to use a hypergeometric function which i've never heard of

p^2.sin(phi)

Joined 06 Sep '04 Moves 25076 -((1+sin(x))^(1/2)*(-2*sin(x)+2)^(1/2)*(-sin(x))^(1/2)*(2*EllipticE((1+sin(x))^(1/2), 1/2*2^(1/2))-EllipticF((1+sin(x))^(1/2),1/2*2^(1/2))))/(cos(x)*sin(x)^(1/2))
Simple really.