- 13 Nov '08 10:31

One off 2^n, where n is some integer?*Originally posted by Andrew Hamilton***Here is a harder one (I think): Anyone care to guess the significance of these #'s ?**relevant)

1048575, 255, 1, 8191

(the order of the numbers is [b]ir

There is more than one way of answering this depending on how you look at it.[/b] - 13 Nov '08 10:39 / 2 edits

Correct: (2^n)-1*Originally posted by FabianFnas***One off 2^n, where n is some integer?**

Also, if you convert any of these numbers to binary numbers, they will consist of all digit 1’s with no digit 0’s.

I find that this is on a very rare occasion useful to know when I am designing my software. - 13 Nov '08 10:50

My assembler programming background helped me a little...*Originally posted by Andrew Hamilton***Correct: (2^n)-1**

Also, if you convert any of these numbers to binary numbers, they will consist of all digit 1’s with no digit 0’s.

I find that this is on a very rare occasion useful to know when I am designing my software. - 16 Nov '08 14:12 / 3 editsAll these sequences have something simple in common -so what is it and how does each sequence continue? And can you add an example of another sequence to this list?

4, 20…

3, 12, 156, 24492, ….

2, 6, 30, 930, …..

1, 2, …..

0.5, 0.75, 1.3125, ….

0, 0, 0, 0, ….

-0.5, -0.25, -0.1875, …..

-1, 0, …..

-2, 2, ….

-3, 6, …..

-4, 12…. - 16 Nov '08 17:17 / 3 editsWow...for some reason I thought 5 + 8 = 11...

Anyways...this problem is difficult since I can't use subscripts, but I'll try my best (and not make a simple mistake).

The pattern is (number)(number+1) = next number. The first numbers are decreasing by one as you go down. The next sequence (down) would be -5, 20, 420, ...

If I'm correct, then the third line is flawed; it should be 2, 6,**42**, ...