Projectile Motion

XanthosNZ

Cancerous Bus Crash

Posers and Puzzles

16 Aug 05

XanthosNZ

Cancerous Bus Crash

p^2.sin(phi)

Joined: 06 Sep 04
Moves: 25076

16 Aug 05

y = x*tan(theta) - (g*x^2) / (2*cos(theta)^2*v^2)

Using a launch speed (v) of 200 ms-1 find the maximum distance (x) at which a height (y) of 1000m can be achieved.

Gravity (g) can be assumed to be 9.8ms-2.

Bowmann

Non-Subscriber

RHP IQ

Joined: 17 Mar 05
Moves: 1345

16 Aug 05

Homework?

XanthosNZ

Cancerous Bus Crash

p^2.sin(phi)

Joined: 06 Sep 04
Moves: 25076

16 Aug 05

2 edits

Originally posted by Bowmann
Homework?

You could say that.
It's an extra question and I can't get my matlab program to work properly. I believe the answer is less than but close to 3000m.

Attempts to attack the equation using Maple fail as the variables are x and theta and for some reason it doesn't seem to like that.

EDIT: Aha. Got it. 2915m with a launch angle of 0.951.

Marinkatomb

wotagr8game

tbc

Joined: 18 Feb 04
Moves: 61941

19 Aug 05

Originally posted by Bowmann
Homework?

Osama wants it handed in today 😛

AThousandYoung

1st Dan TKD Kukkiwon

tinyurl.com/2te6yzdu

Joined: 23 Aug 04
Moves: 26753

25 Aug 05

Originally posted by XanthosNZ
You could say that.
It's an extra question and I can't get my matlab program to work properly. I believe the answer is less than but close to 3000m.

Attempts to attack the equation using Maple fail as the variables are x and theta and for some reason it doesn't seem to like that.

EDIT: Aha. Got it. 2915m with a launch angle of 0.951.

Glad we were able to help.