Please turn on javascript in your browser to play chess.
Posers and Puzzles

Posers and Puzzles

  1. Standard member XanthosNZ
    Cancerous Bus Crash
    16 Aug '05 16:57
    y = x*tan(theta) - (g*x^2) / (2*cos(theta)^2*v^2)

    Using a launch speed (v) of 200 ms-1 find the maximum distance (x) at which a height (y) of 1000m can be achieved.

    Gravity (g) can be assumed to be 9.8ms-2.
  2. Standard member Bowmann
    Non-Subscriber
    16 Aug '05 17:31
    Homework?
  3. Standard member XanthosNZ
    Cancerous Bus Crash
    16 Aug '05 17:45 / 2 edits
    Originally posted by Bowmann
    Homework?
    You could say that.
    It's an extra question and I can't get my matlab program to work properly. I believe the answer is less than but close to 3000m.

    Attempts to attack the equation using Maple fail as the variables are x and theta and for some reason it doesn't seem to like that.


    EDIT: Aha. Got it. 2915m with a launch angle of 0.951.
  4. Subscriber Marinkatomb
    wotagr8game
    19 Aug '05 17:07
    Originally posted by Bowmann
    Homework?
    Osama wants it handed in today
  5. Subscriber AThousandYoung
    It's about respect
    25 Aug '05 18:12
    Originally posted by XanthosNZ
    You could say that.
    It's an extra question and I can't get my matlab program to work properly. I believe the answer is less than but close to 3000m.

    Attempts to attack the equation using Maple fail as the variables are x and theta and for some reason it doesn't seem to like that.


    EDIT: Aha. Got it. 2915m with a launch angle of 0.951.
    Glad we were able to help.