Originally posted by ilywrin
what first comes to mind:
1.d4 e6 2.Bh6 Qh4 3.e3 Qxh2 4.Qh5 g5 5.a4 g4 6.Nf3 g3 7.Qg6 Qh4 8.a5 Qd8 9.Ra4 Nf6 10.Rc4 Ng8 11.Rc6 Nf6 12.Rh4 Ng8 13.Rg4 Nf6 14.f4 Ng8 15.f5 Nf6 16.Ng5 Ng8 but this is missing the bishop at e2
If my calculations are correct, the only way for white to reach the end position in 16 moves is when the h-rook goes to c6 via h6, and the a-rook to g4 via a4. Otherwise, it takes 5 moves at least for the two rooks, instead of 4.
The main problem is when/how black captures the h2-pawn. Possible paths:
- not by the queen (d6 can be played only after the rook moved to c6, but the rook cannot move before the pawn is taken)
- by a knight, but only via g4 (f3 would give check), which has to occur before the white rook occupies g4. Not sure if it is the queens-knight or kings-knight either.
- by the bishop via g7 - e5. This can only be done before the black pawn is on g3.
- by a rook (move knight from g8, rook via g8 - g-file to h-file to h2 and back. The problem is that this takes at least 9 moves before the rook has taken the pawn and is back on the 8-th rank to free the path for the white rook.
Other question (in my plan) is how the queen got to g6: via h4 or via d3 (most likely because that is indifferent to the g4 & g3 square occupation). Via d3 has the difficulty that d4 must be played, which can only be done after the a-rook moved to g4.
So far I have not found a good solution.