22 Oct '05 07:20>
Write the following in Scientific Notation:
3^667 * 2^2 = ? * 10^?
2^10^6 = ? * 10^?
3^667 * 2^2 = ? * 10^?
2^10^6 = ? * 10^?
Originally posted by elopawnthe last one doesn't need a calculator, 2 *10^1,000,000
Write the following in Scientific Notation:
3^667 * 2^2 = ? * 10^?
2^10^6 = ? * 10^?
Originally posted by sonhouseOh wow I totally misread the first one. I thought it said 3*667.
the last one doesn't need a calculator, 2 *10^1,000,000
but most calcs wouldn't be able to do that.
in engineering notation, it would be 2E1,000,000.
The first one is 3^667 * 4, my calc won't do that, maybe my HP48
can, right now, can't find the dang thing. none of the regular
ones do three digit exponents.
Originally posted by AThousandYoung2^10 is 1028??? I was always told its 1024. They cheated me....took so much money....and taught me wrong. :'(
Oh wow I totally misread the first one. I thought it said 3*667.
The second one you are mistaken. 2 to any power is not necessarily going to be 2 to some power of 10. 2^10 is 1028. Then you need to raise that to the 6th power which I did via calculator.
Originally posted by elopawnThis seems a bit like it might be old O level maths homework about logs.
Write the following in Scientific Notation:
3^667 * 2^2 = ? * 10^?
2^10^6 = ? * 10^?
Originally posted by iamatigerI don't understand how you made this jump:
This seems a bit like it might be old O level maths homework about logs.
x = 3^667 * 2 ^ 2
take logs of both sides:
log x = 667 log 3 + 2 log 2
using excel (or log tables) for the logs
log x = 318.8419369
log x - 0.8419369 = 318
using excel (or alog tables) to get 10^0.8416369
log x - log 6.949267029 = 318
alogs of both sides
x/6.949267 ...[text shortened]... og(y) = 10^6.log(2)
log(y) = 301029.9957
log(y) - log(9.9015) = 301029
y = 9.9015*10^301029
Originally posted by AThousandYoungAs per the technique in the first example
I don't understand how you made this jump:
[b]log(y) = 301029.9957
log(y) - log(9.9015) = 301029[/b]