Originally posted by AThousandYoung
For two infinitesimal periods of time, the connecting point A does move perpendicular to the Piston's line of motion. If the Piston is moving in the y direction, then when the Piston is fully extended or retracted (and the Linking Rod is parallel to the Piston's line of motion) then A will be moving perpendicular to the Piston's line of motion. T ...[text shortened]... hile it was moving????
Nope.
It sounds like you've never studied calculus. Have you?[/b]
No I have hot studied calculus.
I did make some incorrect statements unclear statements, sorry.
I'll try to clear them up.
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I meant to say;
Only two
non consecutive points on any circle will give a slope that is a negative reciprocals of vertical line's
slope, making that line perpendicular to the piston's
vertical line on motion.
Those are the two
center points between TDC and BDC.
Not TDC and BDC in our case.
your answer:I don't understand.
Basically that means no two consecutive points on an
arc or circle can be perpendicular to a vertical line. As you yourself answered later.
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I said:
No other point is == TDC in X-value...No other point is == BDC in X-value
on an arc.
I meant to add "on an arc" because I was talking of the circle as two arcs
your answerI don't know what the double equals signs mean, but BDC and TDC have the same x value.
== means "is equal to" in program logic. != means "is not equal to."
Note: TDC means this point is the highest and central point on an arc, BDC makes it the lowest and central point in an arc.
No other point on the arc is >= TDC in Y-value. No other point on this arc == TDC in X-value.
No other point on the arc is <= BDC in Y-value. No other point on this arc == BDC in X-value.
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Q: Better yet, did the connection point spend any more time in TDC or BDC than it did in any other position while it was moving????
A: Nope.
Then how can you convince me that the piston *did* spend *more* time at the top of its stroke, which is TDC(or even BDC)?
It move in relation to the connection point!
I still say it does not stop, but keeps moving at in infinitesimal velocity.
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I said:
Note: TDC means this point is the highest and central point on an arc, BDC makes it the lowest and central point in an arc.
No other point on the arc is >= TDC in Y-value. No other point on this arc == TDC in X-value.
No other point on the arc is <= BDC in Y-value. No other point on this arc == BDC in X-value.
Meaning you cannot use TDC or BDC to create an imaginary perpendicular tangent to the piston's vertical line, because any other point on the arc used for this imaginary perpendicular tangent will have an invalid Y-value.
my bad wording == bad logic
your answer:I don't think you understand the concept of a tangent. A tangent touches a circle at only one point. Therefore your reference to using two points on the arc to define a tangent makes no sense.
But you telling me the single points of TDC and BDC means perpendicular travel makes no sense to me either!
You need two points to make a line. We are talking about an arc, so no points on this arc will be perpendicular or parallel to any line.
You cannot draw a line that is perpendicular to the P's line using TDC or BDC. So you cannot argue that the connection point moves perpendicular to the P's line using TDC or BDC as a reference, or at all.
Tangent lines are outside the connection points line of travel and only touch any single point. including TDC or BDC, so you can't use Tangents to show perpendicular travel of the connection Point.
They have no meaning or bearing on the mechanical operation.
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you said:
In short, Princess is right.
Of course there is a tangent line perpendicular to the piston's line of motion. There are infinite tangent lines to any circle and there are two which have any possible angle relative to the x axis.
my answer:
Infinite tangent lines or not, these lines which are
outside the connection points line of travel and only touch any single point have no meaning or bearing on the mechanical operation.
Where do these lines come from, nothing moves perpindicular to the P's line.
I still say the piston does not stop, but keeps moving at in infinitesimal velocity near at TDC and BDC.
Remember?:
Q: ...did the connection point spend any more time in TDC or BDC than it did in any other position while it was moving????
A: Nope.