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Genius, many formulas express recursion. Mine was f(n,m) = f(n-m,m) + f(n,m-1).I mistyped. The final thing should be:f(500,4) = SUM([n=0 to 125] SUM([k=0 to 4n/3] [(4n-3k)/2] + [4n/3]+1))
cloning vat
I wonder wether being mad is a sign of good chess qualities...😕
Your Blackened Sky
Originally posted by royalchickenGenius, many formulas express recursion. Mine was f(n,m) = f(n-m,m) + f(n,m-1).I mistyped. The final thing should be:f(500,4) = SUM([n=0 to 125] SUM([k=0 to 4n/3] [(4n-3k)/2] + [4n/3]+1))
