Posers and Puzzles
Elsewhere
- Joined
- 29 Nov '02
- Moves
- 17317
Genius, many formulas express recursion. Mine was f(n,m) = f(n-m,m) + f(n,m-1).
I mistyped. The final thing should be:
f(500,4) = SUM([n=0 to 125] SUM([k=0 to 4n/3] [(4n-3k)/2] + [4n/3]+1))
- Joined
- 26 Mar '03
- Moves
- 143
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cloning vat
- Joined
- 07 Feb '03
- Moves
- 16173
I wonder wether being mad is a sign of good chess qualities...😕
Your Blackened Sky
- Joined
- 12 Mar '02
- Moves
- 15128
Originally posted by royalchicken
Genius, many formulas express recursion. Mine was f(n,m) = f(n-m,m) + f(n,m-1).
I mistyped. The final thing should be:
f(500,4) = SUM([n=0 to 125] SUM([k=0 to 4n/3] [(4n-3k)/2] + [4n/3]+1))
yeah-well, i've heard of recursion then...😛 erm-what's recursion?...
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