- 03 May '05 07:24Trapezints are those special trapezia whose sides have integer lengths. The parallel sides are of unequal length. Let a be the length of the shorter of the parallel sides and b,c,d the lengths of the other sides in clockwise order. We write [a,b,c,d] as the name of the trapezint. For example [1,3,5,4] is a trapezint with perimeter 13.

a. What is the shorter perimeter that a trapezint can have? Explain why there is not a smaller one.

b. What is the smallest perimeter of a trapezint with a non-parallel sides having different lengths? Explain why there is not a smaller one.

c. What is the smallest perimeter of a trapezint with at least one angle a right angle? Explain why there is not a smaller one.

d. Find all trapezints with perimeter 9.

Note: here we regard two trapezints as different only if they are not congrunt. In particular [a,b,c,d] and [a,d,c,b] are the same. - 03 May '05 08:31

a. 5 (side lengths 1,1,1,2). You can't get shorter, as [1,1,1,1] is not allowed because parallel sides must have unequal length.*Originally posted by phgao***Trapezints are those special trapezia whose sides have integer lengths. The parallel sides are of unequal length. Let a be the length of the shorter of the parallel sides and b,c,d the lengths of the other sides in clockwise order. We write [a,b,c,d] as the name of the trapezint. For example [1,3,5,4] is a trapezint with perimeter 13.**

a. What is the shorter ...[text shortened]... as different only if they are not congrunt. In particular [a,b,c,d] and [a,d,c,b] are the same.

b. 6 (side lengths 1,1,2,2). You can't get shorter as each pair of opposite sides has unequal length, so one of each pair must have length >1.

c. 14, in the form [1,5,5,3], [1,5,4,4] or a mirror image: If we have one right angle between a parallel side P and a non-parallel side Q, we must have another between the same non-parallel side R and the other parallel. That forms a 'U' shape, only the sides of the U can't be of equal height. By Pythagoras, the length of the remaining side S is given by S = Q^2 + (P-R)^2. The smallest solution to this in positive integers is S = 5, with one of:

Q = 3, P = 5, R = 1

Q = 3, P = 1, R = 5

Q = 4, P = 4, R = 1

Q = 4, P = 1, R = 4

d. No side can be longer than 4 by the triangle inequality; the parallel sides cannot be the same length; and mirror images are considered equivalent. Hence an equivalence class of trapezints with perimeter 9 can be indicated by two unordered pairs of integers between 1 and 4 whose sum is 9: the first pair represents the parallel sides, which must be unequal, and the second pair the other sides. These equivalence classes are as follows:

1,2 3,3

1,2 2,4

1,3 2,3

1,3 1,4

2,3 2,2

2,3 1,3

2,4 1,2

3,4 1,1 - 03 May '05 09:41

I'm no math wizz, but I don't think you can construct a trapezint with lengths 1,1,2,2. What would the interior angles of your 1,1,2,2, trapezint be?*Originally posted by Acolyte***b. 6 (side lengths 1,1,2,2). You can't get shorter as each pair of opposite sides has unequal length, so one of each pair must have length >1.**

I think the actual correct answer is 7 (1,2,3,1). - 03 May '05 22:27

My bad - that trapezint would go a bit flat, wouldn't it There's a restriction I failed to spot: a non-parallel side has to be shorter than |P-Q| + R, where P and Q are the parallel sides and R is the other side. Both 1,2,2,2 and 1,2,3,1 work though - well spotted.*Originally posted by The Plumber***I'm no math wizz, but I don't think you can construct a trapezint with lengths 1,1,2,2. What would the interior angles of your 1,1,2,2, trapezint be?**

I think the actual correct answer is 7 (1,2,3,1).

Hmm, some of those classes of length 9 look dodgy too. Here's an edited list:

1,2 3,3

1,3 2,3

2,3 2,2

2,4 1,2

3,4 1,1 - 24 May '05 07:15
*Originally posted by doublez***3,4,1,1 and others where a >c don't exist, it states that a is the shortest side***Originally posted by phgao***Let a be the length of the shorter of the parallel sides**

If you'll notice, I put the trapezint classes as a pair of parallel sides, followed by a pair of non-parallel sides. So the class 3,4 1,1 consists of the trapezint [3,1,4,1].