- 30 Jan '07 09:12

the sequence of numbers that is to be completed is the title of the thread*Originally posted by MikeBruce***Can you explain that again.... from what you said it sounds like your saying the number that comes next from that sequence is one of the numbers in the sequence. So basically you use a number twice??**

otherwise can you word it "What number comes next in this sequence?"

2 9 3 11 15

and the next number in the sequence is one of the following:

1 29 14 7 8 16

which one is it?

i think this is what the problem was supposed to be, but it is not totally clear from the wording.

this is my interpretation of the way its worded anyway, i dont know if its right or not.

hope this helps someone.....this type of problem really isnt my thing - 30 Jan '07 11:25

yes this is what the problem should sound like.*Originally posted by Joshua B***the sequence of numbers that is to be completed is the title of the thread**

2 9 3 11 15

and the next number in the sequence is one of the following:

1 29 14 7 8 16

which one is it?

i think this is what the problem was supposed to be, but it is not totally clear from the wording.

this is my interpretation ...[text shortened]... know if its right or not.

hope this helps someone.....this type of problem really isnt my thing - 31 Jan '07 00:11 / 2 edits

Actually it HAS to be 14 .. there is another reason for this (other than that was the only number available .. i'm not sure that this was the puzzlers intention but it is an interesting sub relation)*Originally posted by richjohnson***14, although 51, 52, 61 or 62 would also work (8 letters)**

I'll give you a hint .. the next numbers in the sequence after 14 are 49, 29 .. and the twelfth number (if there is an elventh number) in the sequence is 77.

I'll give a cookie to anyone who can prove whether or not the sequence (under the additional relation) is infinite - 31 Jan '07 19:16

The next one could be 3,000.*Originally posted by idioms***Actually it HAS to be 14 .. there is another reason for this (other than that was the only number available .. i'm not sure that this was the puzzlers intention but it is an interesting sub relation)**

I'll give you a hint .. the next numbers in the sequence after 14 are 49, 29 .. and the twelfth number (if there is an elventh number) in the sequence is 77. ...[text shortened]... yone who can prove whether or not the sequence (under the additional relation) is infinite - 31 Jan '07 22:36

nope (3000 only fulfills the first condition). There are 3 relations operating on this sequence. The first is:*Originally posted by sonhouse***The next one could be 3,000.**

1. nth number in the sequence has number of letters in english equal to the number of letters in (n-1)th position + 1.

2,9,3,11,15,14,49,29,x,77,y,z

For the purpose of counting letters there is no "and" so 152 is one hundred fifty two (18 letters) - 03 Feb '07 04:57

no one?*Originally posted by idioms***nope (3000 only fulfills the first condition). There are 3 relations operating on this sequence. The first is:**

1. nth number in the sequence has number of letters in english equal to the number of letters in (n-1)th position + 1.

2,9,3,11,15,14,49,29,x,77,y,z

For the purpose of counting letters there is no "and" so 152 is one hundred fifty two (18 letters)

Alright, the next relation is:

2. If x is the nth number of the sequence and n is odd then x is equal to the difference of the nth+1 and nth+3 numbers of the sequence