Originally posted by royalchickenbut if x = y, then you can substitute y for x and x +x then = 2, no?
Cut the cat's tail off. Wrap it into a circle. Infinite cat's tail.
x=1, y=1.
x = y
x^2 = y^2
x^2 - y^2 = 0
(x+y)(x-y) = 0
x + y = 0
So 2 = 0, divide by 2:
1=0
So 1+1=1.
The fallacy is that dividing by x-y was a division by 0.
Here's something confusing....
Say an international law were passed stipulating that no head of state could inhabit the country of which he or she was in charge. Further, say that the so displaced heads of state inhabited one country, and all heads of state had to live here. Where does its president live?
Not confusing, just Russell's Paradox.
Originally posted by royalchickenIf x+ y = 0 and x = y, doesn't that only apply to zero? 😀
Cut the cat's tail off. Wrap it into a circle. Infinite cat's tail.
x=1, y=1.
x = y
x^2 = y^2
x^2 - y^2 = 0
(x+y)(x-y) = 0
x + y = 0
So 2 = 0, divide by 2:
1=0
So 1+1=1.
The fallacy is that dividing by x-y was a division by 0.
Look at the argument. I am at a loss for what to tell you. Yes, it only aplies to zero, BUT, I just made a logically impeccable argument saying that it also holds true for x=y=1. The only problem was that I INTENTIONALLY divided by zero, to show what happens when one does this. I don;t see why this is so difficult.
Originally posted by royalchickenThey live in Britain - we have no president 🙂
Here's something confusing....
Say an international law were passed stipulating that no head of state could inhabit the country of which he or she was in charge. Further, say that the so displaced heads of state inhabited one country, and all heads of state had to live here. Where does its president live?
Not confusing, just Russell's Paradox.
Originally posted by royalchickenI see...Gotcha....it's not difficult I was just wondering. I'm pretty good at math.....😀 Not quite as good as yourself though!
Look at the argument. I am at a loss for what to tell you. Yes, it only aplies to zero, BUT, I just made a logically impeccable argument saying that it also holds true for x=y=1. The only problem was that I INTENTIONALLY divided by zero, to show what happens when one does this. I don;t see why this is so difficult.