Just to refresh my memory:
If you have 8 proffessors and 8 offices and you have to assign each to 1 office how many different ways are there?
8 P 8 = 40, 320 or 8! = 40, 320.
This is it right?
Just a sidenote here which I was thinking about. You have a chess tourney and you have 6 players and it's a round robin. How many total games?
6 C 2 = 15 right?
Originally posted by RahimK8
Just to refresh my memory:
If you have 8 proffessors and 8 offices and you have to assign each to 1 office how many different ways are there?
8 P 8 = 40, 320 or 8! = 40, 320.
This is it right?
Just a sidenote here which I was thinking about. You have a chess tourney and you have 6 players and it's a round robin. How many total games?
6 C 2 = 15 right?
Originally posted by RahimKI am not sure what the "6 C 2" means, but yes, 15 is right. Every player has to play five games, so that's 30 games divided by 2 because there are always two players involved.
Just a sidenote here which I was thinking about. You have a chess tourney and you have 6 players and it's a round robin. How many total games?
6 C 2 = 15 right?
Originally posted by RahimKOk, explain
what? Don't be a jerk.
you asked "If you have 8 proffessors and 8 offices and you have to assign each to 1 office how many different ways are there? "
Lets call the proffesors A,B,C,D,E,F,G,H,I,& J
And call the offices 1,2,3,4,5,6,7,& 8.
show me more than 8 combinations. . . remember, each gets one office, that's what you said.
Originally posted by huckleberryhoundYou can put A in office 1, B in office 2, ....
Ok, explain
you asked "If you have 8 proffessors and 8 offices and you have to assign each to 1 office how many different ways are there? "
Lets call the proffesors A,B,C,D,E,F,G,H,I,& J
And call the offices 1,2,3,4,5,6,7,& 8.
show me more than 8 combinations. . . remember, each gets one office, that's what you said.
Put A in office 1, B in office 3, C in office 2,.....
Then you can put B in office 1, A in office 2, etc...
Should be 40,320 if we are doing it right.
Originally posted by huckleberryhound12345678
Ok, explain
you asked "If you have 8 proffessors and 8 offices and you have to assign each to 1 office how many different ways are there? "
Lets call the proffesors A,B,C,D,E,F,G,H,I,& J
And call the offices 1,2,3,4,5,6,7,& 8.
show me more than 8 combinations. . . remember, each gets one office, that's what you said.
ABCDEFGH (you added some extra professors 😉)
12345678
ABCDEFHG
12345678
ABCDEGFH
12345678
ABCDEGHF
12345678
ABCDEHFG
12345678
ABCDEHGF
Too lazy to continue, but you get the gist...
The professors are named A, B, C, D, E, F, G and H.
Pick one of them...let's say professor A. He could go into any of the offices since none are occupied. Thus he could be in 8 different places.
No matter which office he gets, the next one...say, Professor B, can be put into any one of 7 rooms. For each of the 8 possibilities for A, there are 7 possibilities for B. 8x7.
Etc.