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Reverse on intellectual challenge game

Reverse on intellectual challenge game

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List 4 words, each having 4 letters.

Then find a word, of the fewest letters, that contains the letters making up each of the 4 words.

If a 4-letter word has one letter twice, eg, "were", then the found word must have at least two of that letter, eg, "weirder" has 2 e's and so we can get "were" from it.

No use of anagram solvers, etc., allowed. Or maybe yes. It's up to the participants, agree beforehand.

Example: "were, drew, dire, deer." A 7 letter word that contains them all, is "weirder." (There may be a shorter word that works. Easy to find out.)

The solver gets to submit the next 4 words.

Any list of 4 words must be "solvable". Their submitter must have a word in mind from which the 4 words can be made. It need not be the shortest possible word. So don't submit jive, quid, axon, and zany, unless you know the word they can be made from.

If not a game for now, maybe someday with the grandkids.

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Originally posted by JS357
List 4 words, each having 4 letters.

Then find a word, of the fewest letters, that contains the letters making up each of the 4 words.

If a 4-letter word has one letter twice, eg, "were", then the found word must have at least two of that letter, eg, "weirder" has 2 e's and so we can get "were" from it.

No use of anagram solvers, etc., allowed. Or may ...[text shortened]... know the word they can be made from.

If not a game for now, maybe someday with the grandkids.
My list:

were
wear
dear
deer

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Originally posted by Ponderable
My list:

were
wear
dear
deer
redraw

I pass on my turn.

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Originally posted by NoEarthlyReason
redraw

I pass on my turn.
It is not your turn, since you have to use the "e" two times, if I understood the rules correctly.
Hint: There is a six-letter word 😉

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Originally posted by Ponderable
My list:

were
wear
dear
deer
dreaded?

No "w". Hmm...

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Originally posted by Grampy Bobby
dreaded?

No "w". Hmm...
I have to admit to have commited a grammatical error in my word 🙁 It is not weared...🙁🙁

So someone else should take a stab

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Originally posted by Ponderable
I have to admit to have commited a grammatical error in my word 🙁 It is not weared...🙁🙁

So someone else should take a stab
I guess I'm the moderator and can't play, but can step in at times like this.

So I used an anagram solver and found

drawee
drôˈē/
noun
noun: drawee; plural noun: drawees

the person or organization, typically a bank, who must pay a draft or bill.

Which makes these 4-letter words, some of which I've never seen before.

awed, awee, dare, dear, deer, dere, draw, dree, drew, ewer, read, rede, reed, wade, ward, ware, wear, weed, weer, were = 20 words

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Originally posted by JS357
I guess I'm the moderator and can't play, but can step in at times like this.

So I used an anagram solver and found

drawee
drôˈē/
noun
noun: drawee; plural noun: drawees

the person or organization, typically a bank, who must pay a draft or bill.

Which makes these 4-letter words, some of which I've never seen before.

awed, awee, dare, dear ...[text shortened]... here are 24 ways to combine 4 items (4x3x2x1) drawee is rich.

edit: the math might be screwy.
No use of anagram solvers, etc., allowed. Or maybe yes. It's up to the participants, agree beforehand.

Example: "were, drew, dire, deer." A 7 letter word that contains them all, is "weirder." (There may be a shorter word that works. Easy to find out.)

The solver gets to submit the next 4 words.

Any list of 4 words must be "solvable". Their submitter must have a word in mind from which the 4 words can be made. It need not be the shortest possible word. So don't submit jive, quid, axon, and zany, unless you know the word they can be made from. (From OP)
?

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The Math is actually a bit screwy, since the 24 refers to the way you can order four (different) items , but we actually have six letters, so the number of permutations is 720...

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Originally posted by Ponderable
The Math is actually a bit screwy, since the 24 refers to the way you can order four (different) items , but we actually have six letters, so the number of permutations is 720...
Yes so I deleted it just before your correction.