11 Mar '15 06:35>1 edit
List 4 words, each having 4 letters.
Then find a word, of the fewest letters, that contains the letters making up each of the 4 words.
If a 4-letter word has one letter twice, eg, "were", then the found word must have at least two of that letter, eg, "weirder" has 2 e's and so we can get "were" from it.
No use of anagram solvers, etc., allowed. Or maybe yes. It's up to the participants, agree beforehand.
Example: "were, drew, dire, deer." A 7 letter word that contains them all, is "weirder." (There may be a shorter word that works. Easy to find out.)
The solver gets to submit the next 4 words.
Any list of 4 words must be "solvable". Their submitter must have a word in mind from which the 4 words can be made. It need not be the shortest possible word. So don't submit jive, quid, axon, and zany, unless you know the word they can be made from.
If not a game for now, maybe someday with the grandkids.
Then find a word, of the fewest letters, that contains the letters making up each of the 4 words.
If a 4-letter word has one letter twice, eg, "were", then the found word must have at least two of that letter, eg, "weirder" has 2 e's and so we can get "were" from it.
No use of anagram solvers, etc., allowed. Or maybe yes. It's up to the participants, agree beforehand.
Example: "were, drew, dire, deer." A 7 letter word that contains them all, is "weirder." (There may be a shorter word that works. Easy to find out.)
The solver gets to submit the next 4 words.
Any list of 4 words must be "solvable". Their submitter must have a word in mind from which the 4 words can be made. It need not be the shortest possible word. So don't submit jive, quid, axon, and zany, unless you know the word they can be made from.
If not a game for now, maybe someday with the grandkids.