Originally posted by DeeceYes, in this case it is pointless because it's a draw no matter what happens. If one of the clocks runs out, it's still a draw because the other side does not have material for a theoretical mate. If neither side can theoretically mate the other, no mattere how poorly the other plays, it's always a draw. So two long kings on the board ends the game.
I have seen games here go on for 100's of moves after it was reduced to king vs king. Seems kinda pointless to me.
Edit: Maybe not so pointless. There is a chance that one player will eventually run out of time.
Originally posted by PedroMYou are absolutely correct Pedro. Never too soon to admit one is wrong! I had confused positions with move order complexity, so apologies to the guy I said was wrong! (you were right). Having had a nights sleep not sure why I misinterpreted the original post(s), but hey, in the context of the Universe it doesn't matter a jot 🙂
My friend Policestate,
Not being confrontational 🙂, I believe you are mixing up 2 different concepts. 10^115 or 10^120 is the game tree complexity, which is not the same as the number of chess positions (10^43). See details here:
http://en.wikipedia.org/wiki/Shannon_number
It takes a little while to understand the difference, but I guess the conclus ...[text shortened]... ble variations. Don't know if this makes sense to you, but this is the way I understand it 😀
As wittywonka rightly summarises, it's a mind-blowing concept whichever way you come at it!
