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  1. Standard member SwissGambit
    Caninus Interruptus
    04 Aug '13 19:01

    White mates in 2
  2. Standard member ptobler
    Patzer
    04 Aug '13 19:24 / 1 edit
    Move 1: King off the back rank (Kf2)
  3. Standard member ptobler
    Patzer
    04 Aug '13 19:25 / 2 edits
    then if 1...Ka1,2 Qxb1#
  4. Standard member ptobler
    Patzer
    04 Aug '13 19:27 / 5 edits
    if instead Black moves the knight, mate Black with Queen on the back rank (viz. 1...Na3, 2 Qa1#; 1...Nc3,2 Qa1#; 1...Nd2 2 Qa1 # )
  5. 04 Aug '13 22:13 / 1 edit
    Two things I hate to see: Mate in X moves and Swiss Gambit's name

    White can also play 1.0-0 and mate next move, a dual solution.
    So we have to prove White cannot castle.

    White's King must have moved to let the Black King in to run along the 1st rank to get to a2.
    Therefore he cannot castle.

    (it's too easy...there will be a catch.)
  6. Standard member SwissGambit
    Caninus Interruptus
    04 Aug '13 22:41
    Originally posted by greenpawn34
    Two things I hate to see: [b]Mate in X moves and Swiss Gambit's name

    White can also play 1.0-0 and mate next move, a dual solution.
    So we have to prove White cannot castle.

    White's King must have moved to let the Black King in to run along the 1st rank to get to a2.
    Therefore he cannot castle.

    (it's too easy...there will be a catch.)[/b]
    Sometimes you lure them in with easier ones first.
  7. 04 Aug '13 23:17
    Change the b1 Knight to a Bishop.


    And it's still a mate in two. (one solution and the position is still legal.)
  8. Subscriber moonbus
    Uber-Nerd
    05 Aug '13 06:47 / 2 edits
    Originally posted by greenpawn34
    Two things I hate to see: [b]Mate in X moves and Swiss Gambit's name

    (it's too easy...there will be a catch.)[/b]
    Assume the White Ps are on the 7th, not the 2d (i.e., the board has been rotated 180 degrees, or, in SG's case, some odd-multiple of 180).
  9. 05 Aug '13 07:23 / 1 edit
    Originally posted by SwissGambit
    [fen]8/8/8/8/8/8/kPP5/1nQ1K2R w - - 0 1[/fen]
    White mates in 2
    The only way the black king could ever have gotten to square a2 is via b1, c1 and d1 or d2. But that is only possible when the king is not on its Original square. It is now, so it has moved at least twice, hence 1. 0- 0- 0 is not possible.

    Edit: i should learn to read first, that's what GP already said before. Only I don't expect another 'catch'
  10. 05 Aug '13 11:20 / 2 edits

    No Catch. SImple standard White to play and mate in two. One key move solution.

    You have always read very very carefully what SG writes.
    If he posts. Mate in Two.

    That means he has a mate, a pal, a friend in the town of Two (wherever that is.)
  11. Subscriber moonbus
    Uber-Nerd
    05 Aug '13 18:19 / 2 edits
    I realize that my previous post did not reveal the solution in its full-fledged form. So, here goes: the White Ps are on the 7th, not the 2d. The White K cannot castle, as GP noted, because it has moved from its original square; it is therefore now on Q8, not K1. The win proceeds in several stages, as follows. Stage 1: sac the rook (SG puzzle, basic rule of thumb). Stage 2: give the opponent 4 passers (SG puzzle, ditto). Stage 3: open a Borg hyperspace conduit. Stage 4: from the Borg hyperspace conduit, reset the universal gravitational constant to 0.94 of its current value. Stage 5: under-promote the two White pawns (on the 7th, not the 2d) to knights. Proceed to mate with 2 knights. This should take no more than 47 moves in total. Stage 6: while exiting the Borg hyperspace conduit, collapse the 47 moves (as explained above) via Lorenz Transformation (physics 101) to two moves. Hey, presto!

    (PS: in the position with a Black bishop instead of a knight, 1. K-Q2/K2/B2 fails against BxP, since Q-R1+ leaves Black an exit square via N6; fails in 2 moves, that is. However 1. R-R3 does win in two moves as follows: either 1. ... BxP; 2. R-R3 mate, or 1. ... K-R8; 2. R-R3 mate)