1. Joined
    22 Sep '06
    Moves
    1707
    21 Sep '08 12:224 edits


    White to move and mate in 4. (He chooses to show off and play the fancy mate as opposed to the mate in 2)
    1. Qxb8 Nxb8 [...Rxb8 2. axb5+ Na5 3. Rxa5#] [...Ka6 2. Qxa8+ Na7 3. Qxa7+ Kxa7 4. axb5#]
    2. axb5 Na6+
    3. Rxa6+ bxa6
    4. b6#
  2. e4
    Joined
    06 May '08
    Moves
    42492
    21 Sep '08 13:18
    Originally posted by Uries
    [fen]rr4Q1/kpK5/2n5/1p6/P7/8/8/R7 w - - 0 1[/fen]

    White to move and mate in 4. (He chooses to show off and play the fancy mate as opposed to the mate in 2)
    1. Qxb8 Nxb8 [...Rxb8 2. axb5+ Na5 3. Rxa5#] [...Ka6 2. Qxa8+ Na7 3. Qxa7+ Kxa7 4. axb5#]
    2. axb5 Na6+
    3. Rxa6+ bxa6
    4. b6#
    A good one. Can you see you have worked at it.

    I was thinking if you replaced the b8 Rook with a Black Queen.
    (Black's last move was 1...Qf8-b8+) then the problem is sound
    without having to add the 'showing off' variation.

    That does mean the problem atarts off with White in check
    which is against most Problem rules. But it works.

    2.Qxb8 Nxb8
    3.axb5+ Na6+
    4.Rxa6 bxa6
    5.b6 mate.
  3. Standard memberSwissGambit
    Caninus Interruptus
    2014.05.01
    Joined
    11 Apr '07
    Moves
    92274
    21 Sep '08 16:181 edit
    Originally posted by greenpawn34
    A good one. Can you see you have worked at it.

    I was thinking if you replaced the b8 Rook with a Black Queen.
    (Black's last move was 1...Qf8-b8+) then the problem is sound
    without having to add the 'showing off' variation.

    That does mean the problem atarts off with White in check
    which is against most Problem rules. But it works.

    2.Qxb8 Nxb8
    3.axb5+ Na6+
    4.Rxa6 bxa6
    5.b6 mate.
    Edit: Thought 4.b6# worked, but 3...Nxa6+ is check.
  4. Joined
    15 Jun '06
    Moves
    16334
    21 Sep '08 16:38
    Originally posted by Uries
    [fen]rr4Q1/kpK5/2n5/1p6/P7/8/8/R7 w - - 0 1[/fen]

    White to move and mate in 4. (He chooses to show off and play the fancy mate as opposed to the mate in 2)
    1. Qxb8 Nxb8 [...Rxb8 2. axb5+ Na5 3. Rxa5#] [...Ka6 2. Qxa8+ Na7 3. Qxa7+ Kxa7 4. axb5#]
    2. axb5 Na6+
    3. Rxa6+ bxa6
    4. b6#
    Yes, like greenpawn says, substitute a queen on b8 for the rook and it will work.... I don't remember saying it is against the rules to start off in check and if I have I will have to ammend that.
  5. Standard memberSwissGambit
    Caninus Interruptus
    2014.05.01
    Joined
    11 Apr '07
    Moves
    92274
    21 Sep '08 16:52
    Originally posted by tomtom232
    Yes, like greenpawn says, substitute a queen on b8 for the rook and it will work.... I don't remember saying it is against the rules to start off in check and if I have I will have to ammend that.
    It's not 'against the rules', but is generally frowned on in a forced-mate type problem, because it makes the problem easier to solve by giving White fewer options for the first move.
  6. Joined
    15 Jun '06
    Moves
    16334
    21 Sep '08 17:01
    Originally posted by SwissGambit
    It's not 'against the rules', but is generally frowned on in a forced-mate type problem, because it makes the problem easier to solve by giving White fewer options for the first move.
    That's why I didn't say I hadn't put it in the rules but having a cooked problem is even worse.... As I am well aware of 😞 I have posted at least two of my own composition on this site that have been busted.
  7. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 19:38


    Black to move. Mate in 8.
  8. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 19:41


    Black to move. Mate in 8.
  9. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 19:44


    Black to move. Mate in 10.
  10. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 19:47


    Black to move. Mate in 10.
  11. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 19:53


    Black to move. Mate in 9.
  12. Joined
    15 Jun '06
    Moves
    16334
    21 Sep '08 19:58
    Originally posted by petrovitch
    [fen]1Q6/p4p1k/6pp/1P1qp3/3b4/6PP/5P2/5K2 b - - 0 1[/fen]

    Black to move. Mate in 8.
    1...Qf3 2.Ke1 (both Qh8+ and Qg8+ get mated sooner) 2...Bc3+ 3.Kf1 Qh1+ 4.Ke2 e4 5.Qh8-g8+ Kxh8-g8 and now 6.b6-g4-h4-f3-f4 and 6... Qe1 is mate if 6.Ke3 then Qf3 is mate.

    These are both good problems but unfortunately this one is cooked and neither of them lead to the desired final position. 🙁
  13. Joined
    08 May '07
    Moves
    55475
    21 Sep '08 20:133 edits
    These all came from my real games. Many of these solutions are not forced or absolute. You just have to find the quickest winning method. In other words, if I tell you it's a mate in 9 then that is the quickest mate that can be found, but by no means the only winning method. And these are not difficult problems; most of them came from blitz games. It was my understanding that these problems were to be original.
  14. Joined
    15 Jun '06
    Moves
    16334
    21 Sep '08 20:58
    Originally posted by petrovitch
    These all came from my real games. Many of these solutions are not forced or absolute. You just have to find the quickest winning method. In other words, if I tell you it's a mate in 9 then that is the quickest mate that can be found, but by no means the only winning method. And these are not difficult problems; most of them came from blitz games. It was my understanding that these problems were to be original.
    The solution I have given is two moves quicker than the stipulation. The problems are supposed to be original but they all have to end in the position in the original post.
  15. Joined
    22 Sep '06
    Moves
    1707
    21 Sep '08 23:123 edits


    Kind of similar to another position posted but extended a bit. Don't think I've seen the promotion idea used yet so here it is.

    Helpmate in 4 moves on the condition that black doesn't move his rook or a pawn.

    1. f3/f4 exf3(ep)
    2. a3 fxg2 [2.a4 forces black to move one of the forbidden pieces]
    3. a4 g1=Q
    4. a5 Qb6+
    5. axb6#
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