- 24 May '07 20:22+1-1=1

this goes to...

+1-1-1=0 when you bring over the 1

thus you're saying that -1=0 not good (the universe implodes or something)

we could also try something crazy and rewrite it as...

+1-(1=1)

same as...

1-1

therefore =0

function stands, though I think it's bad mathematical etiquette to have the brackets on either side of the equals sign, like a split infinitive. - 24 May '07 22:19

in that case it's not a math problem. ()'s cannot start on the left side of = and end on the other.*Originally posted by agryson***+1-1=1**

this goes to...

+1-1-1=0 when you bring over the 1

thus you're saying that -1=0 not good (the universe implodes or something)

we could also try something crazy and rewrite it as...

+1-(1=1)

same as...

1-1

therefore =0

function stands, though I think it's bad mathematical etiquette to have the brackets on either side of the equals sign, like a split infinitive. - 25 May '07 16:35

Take the infinite series that starts +1 - 1 + 1 - 1 + 1 etc*Originally posted by AThousandYoung***Why is this not incorrect?**

Obviously, +1 - 1 + 1 - 1 + 1 ... = +1 - 1 + 1 - 1 + 1 ...

Now apply brackets:

+1 - 1 + (1 - 1) + (1 - 1)... = +1 (- 1 + 1) (- 1 + 1) ...

Each bracket is zero so this leave +1 - 1 = 1

[You can also get to the same result through the more obviously flawed 0 = 1 'argument'. Then, if 0 = 1, it is obvious that +1 - 1 = 1.]