+1-1=1

AThousandYoung

Blondes aren't white

Posers and Puzzles

23 May 07 08:11

AThousandYoung

Blondes aren't white

tinyurl.com/34fnkz3h

Joined: 23 Aug 04
Moves: 28421

23 May 07 08:11

1 edit

Why is this not incorrect?

I wish I knew the right way to ask this Poser without giving it away...

crazyblue

Joined: 29 Apr 05
Moves: 827

23 May 07 11:52

if you have 1 infinity and remove 1 infinity, you still have 1 infinity. was it something like that?

pawnhandler

tinyurl.com/ywohm

Joined: 01 May 07
Moves: 27860

24 May 07 00:50

Originally posted by AThousandYoung
Why is this not incorrect?

I wish I knew the right way to ask this Poser without giving it away...

Because it's correct.

agryson

AGW Hitman

http://xkcd.com/386/

Joined: 23 Feb 07
Moves: 7113

24 May 07 20:22

+1-1=1
this goes to...
+1-1-1=0 when you bring over the 1
thus you're saying that -1=0 not good (the universe implodes or something)

we could also try something crazy and rewrite it as...
+1-(1=1)
same as...
1-1
therefore =0
function stands, though I think it's bad mathematical etiquette to have the brackets on either side of the equals sign, like a split infinitive.

Allderdice

Pittsburgh, PA

Joined: 03 May 07
Moves: 1452

24 May 07 22:19

Originally posted by agryson
+1-1=1
this goes to...
+1-1-1=0 when you bring over the 1
thus you're saying that -1=0 not good (the universe implodes or something)

we could also try something crazy and rewrite it as...
+1-(1=1)
same as...
1-1
therefore =0
function stands, though I think it's bad mathematical etiquette to have the brackets on either side of the equals sign, like a split infinitive.

in that case it's not a math problem. ()'s cannot start on the left side of = and end on the other.

agryson

AGW Hitman

http://xkcd.com/386/

Joined: 23 Feb 07
Moves: 7113

25 May 07 06:13

but it may not be a math problem, that's my point, from what I can see, it can only be true if we add things that aren't given (which is too arbitrary a problem) so I don't think it's simply maths.

agryson

AGW Hitman

http://xkcd.com/386/

Joined: 23 Feb 07
Moves: 7113

25 May 07 06:16

oh, and brackets can be on opposite sides of an = sign, it just prevents it from being an equation on its own. it's a messy way of abbreviating without having to resort to asides.

kbaumen

Sigulda, Latvia

Joined: 30 Aug 06
Moves: 4048

25 May 07 08:14

Perhaps that's a result after a chess match. In that case +1-1=1 means that the player, who has this result, won one game, lost one and drew one.

frankvdgraaff

Joined: 14 Mar 06
Moves: 3210

25 May 07 14:10

because +1 is the same as 1

Diapason

Joined: 21 Sep 05
Moves: 75006

25 May 07 16:35

Originally posted by AThousandYoung
Why is this not incorrect?

Take the infinite series that starts +1 - 1 + 1 - 1 + 1 etc
Obviously, +1 - 1 + 1 - 1 + 1 ... = +1 - 1 + 1 - 1 + 1 ...

Now apply brackets:
+1 - 1 + (1 - 1) + (1 - 1)... = +1 (- 1 + 1) (- 1 + 1) ...
Each bracket is zero so this leave +1 - 1 = 1

[You can also get to the same result through the more obviously flawed 0 = 1 'argument'. Then, if 0 = 1, it is obvious that +1 - 1 = 1.]

AThousandYoung

Blondes aren't white

tinyurl.com/34fnkz3h

Joined: 23 Aug 04
Moves: 28421

30 May 07 09:27

Originally posted by kbaumen
Perhaps that's a result after a chess match. In that case +1-1=1 means that the player, who has this result, won one game, lost one and drew one.

You got it, bud, or close enough. It's some GM's (I forget who) record against Fischer.

FabianFnas

Joined: 11 Nov 05
Moves: 43938

31 May 07 13:11

-1 = 1
Proof:
-1 = sqr(-1)^2 = sqr(-1) * sqr(-1) = sqr(-1 * -1) = sqr(1) = 1
Hence -1 = 1

kbaumen

Sigulda, Latvia

Joined: 30 Aug 06
Moves: 4048

31 May 07 14:42

Originally posted by FabianFnas
-1 = 1
Proof:
-1 = sqr(-1)^2 = sqr(-1) * sqr(-1) = sqr(-1 * -1) = sqr(1) = 1
Hence -1 = 1

i=-1^(1/2)
-1=1
sqrt(-1)=sqrt(1)
i=1 hence
1 = -1^(1/2)