06 Nov 07
Given:
1.) all players on this site have a rating of p1200
2.) ratings are calculated using formulas used on this site (see FAQ Thread of Help Forum for the formulas) with one exception: players lose no points for losses to players rated 720 points higher than themselves.
Design:
Most efficient system for one player to achieve a rating of zero.
What is the minimum number of players required to help one player achieve the rating of zero?
08 Nov 07
Originally posted by rubberjaw30Minimum number of players to get to 0, given initial players all have 1200 (setting aside provisional status for the moment).
Given:
1.) all players on this site have a rating of p1200
2.) ratings are calculated using formulas used on this site (see FAQ Thread of Help Forum for the formulas) with one exception: players lose no points for losses to players rated 720 points higher than themselves.
Design:
Most efficient system for one player to achieve a rating of zero.
What is the minimum number of players required to help one player achieve the rating of zero?
A pair of players with equal rating can theoretically work to get one player's rating down by 360 points (720 difference no longer changes ratings).
So you need one pair of players to get down to 840, two pairs to get to 480, four pairs to get to 120, and one 600 rating player to get to 0. To get the 600 player, you need a pair of 960 players, and thus about four 1200 players. So, you need at minimum 12 players to cooperate for one to reach zero.
I suspect that starting with provisional status would accelerate this process, as you could lose rating points in larger chunks. This is obviously not the most efficient way to reach zero.
09 Nov 07
Originally posted by sven1000good! it may not be right, but it may be... and it's a start anyway...
Minimum number of players to get to 0, given initial players all have 1200 (setting aside provisional status for the moment).
A pair of players with equal rating can theoretically work to get one player's rating down by 360 points (720 difference no longer changes ratings).
So you need one pair of players to get down to 840, two pairs to get to 480, ...[text shortened]... se rating points in larger chunks. This is obviously not the most efficient way to reach zero.
I'll try to post the formulas tomorrow, that should make all of this a bit easier...
10 Nov 07
Originally posted by rubberjaw30In reality it has been shown that if you attempt that, you will be booted from the site. The last one was GOME, removed on the (b) rule.
good! it may not be right, but it may be... and it's a start anyway...
I'll try to post the formulas tomorrow, that should make all of this a bit easier...
However, take a look at the games, they were all self help games, don't forget, when you design games for one player to go down, the other player goes up and the mods did not like GOME doing that and axed him.
11 Nov 07
Originally posted by sonhouseI'm posing the question as a mathematical problem, not to be put into practice.
In reality it has been shown that if you attempt that, you will be booted from the site. The last one was GOME, removed on the (b) rule.
However, take a look at the games, they were all self help games, don't forget, when you design games for one player to go down, the other player goes up and the mods did not like GOME doing that and axed him.
13 Nov 07
Originally posted by AThousandYoungoh oh oh oh!
You said above that you were going to attempt it.
I see now, when what's-his/her-face said are you going to attempt it, I interpreted it as " are you going to try to solve it"
my mistake!
no, I will not be trying to hit zero for obvious reasons. but in my free time, I'll try to solve the problem I gave!
apologies for confusion.