1. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
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    28 Dec '04
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    53223
    05 Dec '08 08:34
    Bases don't have to be rational.
  2. Joined
    21 Feb '06
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    6830
    05 Dec '08 10:36
    Originally posted by sonhouse
    Bases don't have to be rational.
    Surely you can only use the digits 0, 1, 2 and 3 in base pi?
  3. Standard memberwolfgang59
    Quiz Master
    RHP Arms
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    05 Dec '08 13:19
    If it has a meaning
    pi^4 + 3pi^3 + 6pi^2 + 7pi + 6/pi

    I suppose?!?!?
  4. Joined
    21 Feb '06
    Moves
    6830
    05 Dec '08 14:21
    Originally posted by wolfgang59
    If it has a meaning
    pi^4 + 3pi^3 + 6pi^2 + 7pi + 6/pi

    I suppose?!?!?
    No, it would be pi^3 + 3.pi^2 + 6.pi + 7 + 6/pi
  5. Subscribersonhouse
    Fast and Curious
    slatington, pa, usa
    Joined
    28 Dec '04
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    53223
    05 Dec '08 16:51
    Originally posted by Fat Lady
    Surely you can only use the digits 0, 1, 2 and 3 in base pi?
    I was lying down going to sleep and I realized I shouldn't use so many digits, was thinking about binary, 0 and 1, octal, 0-8 and so forth so it must be only 0,1,2,3 for PI. So what would 1223.22 be in PI?
  6. Joined
    31 May '07
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    696
    05 Dec '08 17:08
    1223.22 in base pi

    is

    pi^3 + 2pi^2 + 2pi + 3 + 2/pi + 2/(pi^2) in base 10

    I think it's better leaving it in base pi.
  7. Standard memberwolfgang59
    Quiz Master
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    48793
    08 Dec '08 08:51
    Originally posted by Fat Lady
    No, it would be pi^3 + 3.pi^2 + 6.pi + 7 + 6/pi
    😳
    the shame ................
  8. Joined
    11 Nov '05
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    43938
    08 Dec '08 09:48
    A arbitrarily chosen base, integer, rational, end even real bae, never done that, very interesting.

    The formula goes: sum{a(i)*b^i}
    where i is an integer from low to high,
    and b is a real base > 1, I suppose?

    It doesn't make sense if b < 0, and definitely not when b=1, correct?

    Can we use the formula to construct any real number?
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