- 04 Apr '06 00:15

I timed myself it took 16.3458761298736753462355 seconds. Unfortunately that is as accurate as my watch gets so I may have been slightly slower or slightly faster.*Originally posted by Narragansett***On one chess board, place 8 pawns on the board... pretending they are all queens ....place them in such a position where no one queen can capture the other...another words there must be one on each row, one on each file and cant be placed on the same diagonal...start timing yourself** - 11 Apr '06 05:24

one problem....*Originally posted by Narragansett***On one chess board, place 8 pawns on the board... pretending they are all queens ....place them in such a position where no one queen can capture the other...another words there must be one on each row, one on each file and cant be placed on the same diagonal...start timing yourself**

it is impossible to do that - 11 Apr '06 09:46

Oh really?*Originally posted by ray1993***one problem....**

it is impossible to do that

There are 92 different solutions for an 8x8 board with 8 queens, 12 of these are unique solutions and the remaining 80 can be found from these 12 by rotations and translations.

Here is a method for finding a solution for a nxn board with n queens (n=1 or n>3):

1. Divide n by 12. Remember the remainder (it's 8 for the eight queens puzzle).

2. Write a list of the even numbers from 2 to n in order.

3. If the remainder is 3 or 9, move 2 to the end of the list.

4. Write the odd numbers from 1 to n in order, but, if the remainder is 8, switch pairs (i.e. 3, 1, 7, 5, 11, 9, &hellip.

5. If the remainder is 2, switch the places of 1 and 3, then move 5 to the end of the list.

6. If the remainder is 3 or 9, move 1 and 3 to the end of the list.

7. Place the first-column queen in the row with the first number in the list, place the second-column queen in the row with the second number in the list, etc.

A slightly more challenging problem is to place 9 queens and a pawn on a chessboard such that no queen attacks any other queen. What about placing 10 queens and 2 pawns? - 12 Apr '06 04:32

hey sure showed you're ass, ray*Originally posted by XanthosNZ***Oh really?**

[fen]3Q4/6Q1/2Q5/7Q/1Q6/4Q3/Q7/5Q2 w - - 0 1[/fen]

There are 92 different solutions for an 8x8 board with 8 queens, 12 of these are unique solutions and the remaining 80 can be found from these 12 by rotations and translations.

Here is a method for finding a solution for a nxn board with n queens (n=1 or n>3):

1. Divide n by 12. Remem ...[text shortened]... hessboard such that no queen attacks any other queen. What about placing 10 queens and 2 pawns?