- 29 Jan '08 01:18 / 1 editFor you arithmeticians out there the premise is simple:

Using only the numbers that make up this year: 2,0,0,8 (and all of them once) you must try and construct all the numbers between 0 and 100 (or beyond!)

You may use the following:

- parentheses

- addition

- subtraction

- multiplication

- division

- concatenation (ie: 02 or 80)

- exponentiation (you may use the minus sign for reciprocals)

- factorials (not sub-factorial)

- decimals finite or recurring (1/5 and 2/9 can be represented as .2 and .2bar respectively)

- square root (ie: sqrt(2) )

Here are a few to get you started:

0 = 0*(0 + 2 + 8)

1 = (0 + 2 + 8)^0

2 = 2 + 0*(0 + 8)

3 = 2 + 8^0 + 0

4 = 8/2 + 0 + 0

5 = .2^(-(0!)) + 0*8

6 = 8 - 2 + 0 + 0

7 = 8 - 2^0 + 0

8 = ? - 29 Jan '08 09:19

So you can only use a minus sign in a substraction and in a power?*Originally posted by Agerg***For you arithmeticians out there the premise is simple:**

Using only the numbers that make up this year: 2,0,0,8 (and all of them once) you must try and construct all the numbers between 0 and 100 (or beyond!)

You may use the following:

- parentheses

- addition

- subtraction

- multiplication

- division

- concatenation (ie: 02 or 80)

- exponentiation (yo ...[text shortened]... = 2 + 8^0 + 0

4 = 8/2 + 0 + 0

5 = .2^(-(0!)) + 0*8

6 = 8 - 2 + 0 + 0

7 = 8 - 2^0 + 0

8 = ? - 02 Feb '08 20:1814 = 8x2-0!-0!

15 = 8x2-0!-0

16 = 8x2-0+0

17 = 8x2+0+0!

18 = 8x2+0!+0!

19 = 20-(8x0)!

20 = 20-(8x0)

21 = 20+(8x0)!

22 = (2 catanation 0!)+(8x0)!

23 = (2+0!)x8-0!

24 = (2+0!)x8-0

25 = (2+0)!x8+0!

26 = 2 catanation (8-0!-0!)

27 = 2 catanation (8-0!-0)

28 = 2 catanation (8-0+0)

29 = 2 catanation (8+0!+0)

30 = 2 catanation (8+0!+0!) - 03 Feb '08 02:33 / 2 edits

Unfortunately you cannot concatenate in the way you have demonstrated above.*Originally posted by twilight2007***14 = 8x2-0!-0!**

15 = 8x2-0!-0

16 = 8x2-0+0

17 = 8x2+0+0!

18 = 8x2+0!+0!

19 = 20-(8x0)!

20 = 20-(8x0)

21 = 20+(8x0)!

22 = (2 catanation 0!)+(8x0)!

23 = (2+0!)x8-0!

24 = (2+0!)x8-0

25 = (2+0)!x8+0!

26 = 2 catanation (8-0!-0!)

27 = 2 catanation (8-0!-0)

28 = 2 catanation (8-0+0)

29 = 2 catanation (8+0!+0)

30 = 2 catanation (8+0!+0!)

Valid would be 20 + 08 or 28 + 0! + 0!

Invalid would be 8 concatenated with ((2 + 0!)! - 0!) or any other variations of this theme.

to write such numbers without the word "concatenate" would either render the end result meaningless or give a number different to what you intended.