27 Feb '07 09:17

Before you are 10 vases, of which 9 have identical weight, and one is either lighter or heavier (you're not sure which). You have a simple balance scale capable of holding 5 vases on each side.

I believe I was able to do so in 3 weighings back when I first looked at this problem, but the solution was somewhat involved to explain.

*How can you find the odd vase in the fewest weighings AND determine if it is heavier or lighter than the other 9?*I believe I was able to do so in 3 weighings back when I first looked at this problem, but the solution was somewhat involved to explain.