19 Jan '10 01:49>
Originally posted by sonhousethis also has no solution, you need to know how long it accelerates.
So how much energy does it take to make say, 1 kg, accelerate at one G?
It's not rocket science for god's sake🙂
No, wait....
Originally posted by sonhousePower adds energy at a steady rate.
So how much energy does it take to make say, 1 kg, accelerate at one G?
It's not rocket science for god's sake🙂
No, wait....
Originally posted by sonhouseThink about what your saying, this statment implies that you could with this finite amount of energy accelerate a mass indefinately........NOT POSSIBLE.
So how much energy does it take to make say, 1 kg, accelerate at one G?
It's not rocket science for god's sake🙂
No, wait....
Originally posted by AThousandYoungThat is 100 percent not true. If you look at the ion rockets flying in space right now, they shoot out of the rocket enough to give a constant acceleration with a constant input of energy, albeit a low acceleration and a lot of energy for the acceleration you actually achieve but it is a constant I can gaaaruuntee!
Power adds energy at a steady rate.
Added energy adds to the kinetic energy.
K = mv^2/2
If K is 1 and m is 2,
1 = v^2
v = 1
If K is 4, v = 2
If K is 9, v = 3
If K is 16, v = 4
Now suppose K increases by 1 every second (similar to the OP problem). The rate of acceleration will slow because the velocity only increases with th ...[text shortened]... rt, constant power on constant mass apparently causes an acceleration which decreases over time.
Originally posted by joe shmoI already specified we are not talking about relativistic acceleration, just what you need to get around our solar system, say not going over 10 thousand miles per second or so.
Think about what your saying, this statment implies that you could with this finite amount of energy accelerate a mass indefinately........NOT POSSIBLE.
Originally posted by joe shmoWhat do you think I defined? E. One megawatt. Jeez.
Think about what your saying, this statment implies that you could with this finite amount of energy accelerate a mass indefinately........NOT POSSIBLE.
Energy of a body in motion
E = 1/2*m*v^2 (eq 1)
v =a*t (eq 2)
substitute (eq 2) into (eq1)
E = 1/2*m*(a*t)^2
as it stands this equation has 4 variables of which you have only defined 2 of them. Either t or E must also be defined for there to be a solution
Originally posted by sonhouseI will have look at them throughout the week(they look to be information dense)
What do you think I defined? E. One megawatt. Jeez.
Getting close to c is what the fitzgerald contraction formula is all about.
Did you read my PM's?
Of course you add kinetic energy to a body under acceleration, call it a battery, so what? Ion rockets do that by accelerating at a constant but low acceleration, the total kinetic energy always goes up. That's just the way the cookie crumbles!
Originally posted by joe shmook, Power, I thought I mentioned using a constant input of energy per second which is power. Is that what is tying this all up?
I will have look at them throughout the week(they look to be information dense)
First of all you asked for the "ENERGY", and Second a MegaWatt is NOT a unit of ENERGY, its a unit of power. Power= Energy/time
Originally posted by sonhouseacceleration is not a measure of power
ok, Power, I thought I mentioned using a constant input of energy per second which is power. Is that what is tying this all up?
Acceleration is ALREADY a measure of power, you have to have the time in the equation or you get no acceleration.
Maybe I should have said one megawatt constantly applied.
When I see a power supply rated as one kilowatt, I aut ...[text shortened]... much mass the thing can accelerate for one second which will be the same answer I gave in my PM.
Originally posted by joe shmoYou still have to use power to accelerate and acceleration implies power by having time as one of the units so it sure looks related to me, not directly but indirectly. You have to use power for a given amount of time to show an acceleration. So you still don't agree with my analysis given I said applying 1 megawatt continuously?
acceleration is not a measure of power
in SI units
units of accelration: (m/s^2)
units of Power: [(kg*m/s^2)*m]/s or (kg *(m^2)/(s^3))
They are not the same.
Originally posted by sonhouseThis is explicitly solvable as stated
You still have to use power to accelerate and acceleration implies power by having time as one of the units so it sure looks related to me, not directly but indirectly. You have to use power for a given amount of time to show an acceleration. So you still don't agree with my analysis given I said applying 1 megawatt continuously?
BTW, I hope you don't th ...[text shortened]... eresting the way this post has gone, it causes me to think more carefully about my constructs.