Originally posted by elopawnMm - Ww + Wm - Mw
If the product of a woman's present age (W) and wedding age (w) is subtracted from the product of her husband's present age (M) and wedding age (m) and the result of this is added to (Wm-Mw) the result is 553. Find the present ages.
= M(m - w) + W(m - w)
= (M + W)(m - w)
But M - m = W - w
So m - w = M - W
Hence (M + W)(M - W) = 553 = 79*7
M = 43
W = 36
Originally posted by THUDandBLUNDERYep that's it. Good work.
Mm - Ww + Wm - Mw
= M(m - w) + W(m - w)
= (M + W)(m - w)
But M - m = W - w
So m - w = M - W
Hence (M + W)(M - W) = 553 = 79*7
M = 43
W = 36
If you still dont get it.....
We have Mm-Ww+Wm-Mw = 553
Hence M(m-w)+W(m-w) = 553
Therefore (M + W)(m - w) = 553 = 7*79
Let x be the number of years between the wedding and the present day. Then m = M-x, w = W-x and m-w = M-x-W+x = M-W
Hence (M + W)(M - W) = 7*79
Then either M+W = 553 ( this is not reasonable as the couple would be too old)
or M+W = 79
Then M-W = 7. Adding these gives 2M = 79+7 = 86 and M=43
Then W = 43 - 7 = 36
Basically what TB said. You should be able to get it now Schumi.