There are 50 animals. Some are parakeets and some are dogs. The 50 animals have collectively 140 legs. There are no gimped animals with less than (or more than) the usual number of legs. How many are dogs and how many are parakeets?

Explain in detail how you solved it. This problem was given to elementary school kids who had not yet taken any algebra, so no algebra allowed.

Oddly enough, math on that level is invisible algebra. You're just not directly referring to x's and y's, but you're using many of the same techniques.

Originally posted by geepamoogle Oddly enough, math on that level is invisible algebra. You're just not directly referring to x's and y's, but you're using many of the same techniques.

Originally posted by sonhouse First assume how many legs if all dog, 50*4=200. 200-140=60
60/2=30 parakeets, 50-30=20 Dogs (20*4=80), 80 legs +60 legs=140

So it's easy to do either starting with minimum or maximum legs.