20 Mar 04
Interesting puzzle and I would like to try it...but I know nothing of the scoring in darts (other than what you let me know in your example). Is it this simple:
each dart can be worth 50 (bullseye), 0 (miss the target entirely),
or 1x, 2x or 3x where x is an integer between y and z
I would just need to know what are the values of y and z.
Thanks!
20 Mar 04
Originally posted by ddebenedwhat i would like to know is how many different combinations there are with only _6_ darts to get 301 points.
Interesting puzzle and I would like to try it...but I know nothing of the scoring in darts (other than what you let me know in your example). Is it this simple:
each dart can be worth 50 (bullseye), 0 (miss the target entirely),
or 1x, 2x or 3x where x is an integer between y and z
I would just need to know what are the values of y and z.
Thanks!
the circle in darts is divided into 20 sections. and then each part of the circle (except for the middle) is divided in to 4 sections in order from outside to inside (double, single, triple, single). the middle bulls-eye for most are 50 points but some games its 25 and 50 (outer and inner) but for this the whole area is 50 points.
HAPPY HUNTING!! 😀
21 Mar 04
Originally posted by rattlerz28In other words, there are 81 targets which count as 'different' for the purposes of this puzzle.
what i would like to know is how many different combinations there are with only _6_ darts to get 301 points.
the circle in darts is divided into 20 sections. and then each part of the circle (except for the middle) is divided in to 4 sections in order from outside to inside (double, single, triple, single). the middle bulls-eye for most are 50 points ...[text shortened]... its 25 and 50 (outer and inner) but for this the whole area is 50 points.
HAPPY HUNTING!! 😀
21 Mar 04
yes. but for the purpose of this i want to know how many times 301
points can be achieved with only 6 darts? iknow the obvious one (5 bulls and a triple 17) and if your real cute ( 5 triple 20's and a single 1!) how many more after that.
HAPPY HUNTING!!!!!! 😀😀😀😀
22 Mar 04
1 edit
Originally posted by rattlerz28five 3*(triple-)19 (285) and a 16 or 2*(double-)8 are two.
yes. but for the purpose of this i want to know how many times 301
points can be achieved with only 6 darts? i know the obvious one (5 bulls and a triple 17) and if you're real cute (5 triple 20s and a single 1!) how many more after that?
HAPPY HUNTING!!!!!! 😀😀😀😀
four 3*20 (240) plus any of: 2*20 and 3*7, 3*19 plus 4, 3*18 plus 7, 3*17 plus 10, 3*16 plus 13, 3*15 plus 16, 3*14 plus 19, or bull plus 11 (each adding up to 61) are eight more.
four 3*19 (228) plus any of: 3*20 plus 13, 3*19 plus 16, or 3*18 plus 19 (73) (three more).
four 3*18 (216), 3*15, and 2*20 make one more.
four 3*17 (204), 3*19, and 2*20 are yet another.
three 3*20 (180) plus any of: two 3*19 plus 7, two 3*18 plus 13, two 3*17 plus 19, or two bulls plus 3*7 (121) also do it (four more combos).
three 3*19 (171) plus any of: two 3*20 and 10, or bull and: 3*20 and 20 (or 2*10), 3*18 and 2*13, 3*16 and 2*16, 3*14 and 2*19 (130) also comprise 301 (six more).
three 3*18 (162) plus any of: two 3*20 and 19 or two bulls and 3*13 (139) are two.
that brings us to three 3*17 (153) plus: two 3*20 and 2*14, two 3*19 and 2*17, two 3*18 and 2*20, two bulls and 3*16, or bull, 3*20, and 2*19 (148) (another five).
lastly, three 3*16 (144), two bulls, and 3*19 (157)--probably as far as we can go.
i presume we are talking unique combinations (shot-order-independent), so five 3*20 plus 1 is the same as two 3*20, 1, and three more 3*20.
can anyone come up with more? that above plus the two original come to 35, i believe.