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Posers and Puzzles

Posers and Puzzles

  1. 24 Feb '04 07:18
    this is my first attempt at starting a thread, but here goes
    how many different combinations of 6 darts will it take to get to 301 (for example 5 bulls eyes [50/bull for 250] and a triple 17 [51 points])
  2. 20 Mar '04 00:39
    i would say 8 - 10 different ways to get to 301
  3. 20 Mar '04 01:55
    Interesting puzzle and I would like to try it...but I know nothing of the scoring in darts (other than what you let me know in your example). Is it this simple:

    each dart can be worth 50 (bullseye), 0 (miss the target entirely),
    or 1x, 2x or 3x where x is an integer between y and z

    I would just need to know what are the values of y and z.

    Thanks!
  4. 20 Mar '04 20:09
    Originally posted by ddebened
    Interesting puzzle and I would like to try it...but I know nothing of the scoring in darts (other than what you let me know in your example). Is it this simple:

    each dart can be worth 50 (bullseye), 0 (miss the target entirely),
    or 1x, 2x or 3x where x is an integer between y and z

    I would just need to know what are the values of y and z.

    Thanks!
    what i would like to know is how many different combinations there are with only _6_ darts to get 301 points.

    the circle in darts is divided into 20 sections. and then each part of the circle (except for the middle) is divided in to 4 sections in order from outside to inside (double, single, triple, single). the middle bulls-eye for most are 50 points but some games its 25 and 50 (outer and inner) but for this the whole area is 50 points.

    HAPPY HUNTING!!
  5. Donation Acolyte
    Now With Added BA
    21 Mar '04 11:32
    Originally posted by rattlerz28
    what i would like to know is how many different combinations there are with only _6_ darts to get 301 points.

    the circle in darts is divided into 20 sections. and then each part of the circle (except for the middle) is divided in to 4 sections in order from outside to inside (double, single, triple, single). the middle bulls-eye for most are 50 points ...[text shortened]... its 25 and 50 (outer and inner) but for this the whole area is 50 points.

    HAPPY HUNTING!!
    In other words, there are 81 targets which count as 'different' for the purposes of this puzzle.
  6. 21 Mar '04 17:07
    yes. but for the purpose of this i want to know how many times 301
    points can be achieved with only 6 darts? iknow the obvious one (5 bulls and a triple 17) and if your real cute ( 5 triple 20's and a single 1!) how many more after that.
    HAPPY HUNTING!!!!!!
  7. 22 Mar '04 00:16 / 1 edit
    Originally posted by rattlerz28
    yes. but for the purpose of this i want to know how many times 301
    points can be achieved with only 6 darts? i know the obvious one (5 bulls and a triple 17) and if you're real cute (5 triple 20s and a single 1!) how many more after that?
    HAPPY HUNTING!!!!!!
    five 3*(triple-)19 (285) and a 16 or 2*(double-)8 are two.
    four 3*20 (240) plus any of: 2*20 and 3*7, 3*19 plus 4, 3*18 plus 7, 3*17 plus 10, 3*16 plus 13, 3*15 plus 16, 3*14 plus 19, or bull plus 11 (each adding up to 61) are eight more.
    four 3*19 (228) plus any of: 3*20 plus 13, 3*19 plus 16, or 3*18 plus 19 (73) (three more).
    four 3*18 (216), 3*15, and 2*20 make one more.
    four 3*17 (204), 3*19, and 2*20 are yet another.
    three 3*20 (180) plus any of: two 3*19 plus 7, two 3*18 plus 13, two 3*17 plus 19, or two bulls plus 3*7 (121) also do it (four more combos).
    three 3*19 (171) plus any of: two 3*20 and 10, or bull and: 3*20 and 20 (or 2*10), 3*18 and 2*13, 3*16 and 2*16, 3*14 and 2*19 (130) also comprise 301 (six more).
    three 3*18 (162) plus any of: two 3*20 and 19 or two bulls and 3*13 (139) are two.
    that brings us to three 3*17 (153) plus: two 3*20 and 2*14, two 3*19 and 2*17, two 3*18 and 2*20, two bulls and 3*16, or bull, 3*20, and 2*19 (148) (another five).
    lastly, three 3*16 (144), two bulls, and 3*19 (157)--probably as far as we can go.
    i presume we are talking unique combinations (shot-order-independent), so five 3*20 plus 1 is the same as two 3*20, 1, and three more 3*20.
    can anyone come up with more? that above plus the two original come to 35, i believe.